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HACTEHA [7]
2 years ago
15

Factor −1/2 out of −1/2x+6.

Mathematics
1 answer:
Minchanka [31]2 years ago
6 0

Answer:

Step-by-step explanation:

socratic.org/questions/how-do-you-factor-1-2-out-of-1-2x-6#630699

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The formula for the eres of a triangle is A=2/1bh what is h equal to in terms of a and b
Kisachek [45]
Actually the formula for the area of a triangle is A = 1/2bh.

First step: multiply both sides by 2, to get rid of the 1/2.

2A = bh

Now divide both sides by b.

2A/b = h or h = 2A/b
3 0
3 years ago
The triangles below are similar. Find the length of the missing side (giving brainliest and thanks to all!)
andreev551 [17]

Answer:

x = 4

Step-by-step explanation:

I think this is correct

7 0
2 years ago
Read 2 more answers
What is the measure of each interior angle of the regular polygon pictured below? If necessary, round to the nearest tenth.
sammy [17]

Answer:

144

Step-by-step explanation:

Sum of interior angles:

180(n-2)

180(10-2)  

1440

Measure of each interior angle:

1440/10=144

8 0
2 years ago
Which of the following statements is not true about the numbers 7 and -7?
leonid [27]

Answer:

incorrect is They have a sum of -14

4 0
3 years ago
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
7 0
3 years ago
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