Don't understand your question .

Recall that a circle of radius 2 centered at the origin has equation

where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius

is

, it follows that the area of a quarter-circle would be

.
You have

, so the definite integral is equal to

.
Another way to verify this is to actually compute the integral. Let

, so that

. Now

Recall the half-angle identity for cosine:

This means the integral is equivalent to
Answer:
317 degrees
Step-by-step explanation:
Answer:
Then maybe pay attention in class and know what to do and not ask strangers for help. We answer to try and help. Not like we get paid. We literally are just trying to help
Answer:
there is 2 cakes for each pie.
Step-by-step explanation: