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3 years ago

Express this rate as a unit rate: $50 for 4 days of work. Note: You must label your unit rate.

Mathematics

1 answer:

Andrews [41]3 years ago

7 0

Answer:

12.50 dollars per day

Step-by-step explanation:

This is a fraction equal to

50 dollars ÷ 4 days

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 4

50 dollars ÷ 4

4 days ÷ 4

12.5 dollars

1 day

12.5 dollars

day

= 12.5 dollars per day

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A survey was taken of students in math classes to find out how many hours per day students spend

Hoochie [10]

Answer:

1. Mean, because there are no outliers that affect the center

Step-by-step explanation:

Second period: 3,2,3,1,3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

Sorted values : 0, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4

The mean = ΣX / n

n = sample size, n = 15

Mean = 34 / 15 = 2.666

The median = 1/2(n+1)th term.

1/2(16)th term = 8th term.

The 8th term = 2

The best measure of centre is the mean because the values for the second period has no outliers that might have affected the centre of the distribution.

Both interquartile range and standard deviation are measures of spread and not measures of centre.

6 0

3 years ago

How do you solve / figure 8 x 51 (Distributive property)

Step2247 [10]

8(51)

=8(50+1)

=(8*50)+(8*1)

=(8*5*10)+(8*1)

=400+8

=408

5 0

3 years ago

A man earned x pesos in 10 days and spent y pesos during each of those days. Write an expression to determine how many pesos he

Vsevolod [243]

Answer: $\dfrac{x}{10}-y$

Step-by-step explanation:

Given : A man earned x pesos in 10 days and spent y pesos during each of those days.

i.e. Total earning in 10 days = x

Earning per day = $\dfrac{x}{10}$ [By unitary method] (1)

Money spent per day =y (2)

We know that

$\text{Savings = Money earned - Money spent}$

i.e. Subtract (2) from (1), we get

$\text{Savings = }\dfrac{x}{10}-y$

Hence, the expression to determine how many pesos he saved per day will be:-

$\dfrac{x}{10}-y$

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3 years ago

find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)

Paraphin [41]

This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c

c = 1

If c =1,

6 = a + 1
a = 5

This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?

5 0

3 years ago

What is 10 2/1 divided by 2 1/4

stepladder [879]

Answer:

5.3 but the three is repeated

Step-by-step explanation:

6 0

3 years ago

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