A graph of a quadratic function is shown on the grid.

Mathematics

1 answer:

myrzilka [38]2 years ago

7 0

Answer:

D) (1,-2)

Step-by-step explanation:

The vertex for a quadratic function is either the minimum point or the maximum point of the curve depending on the nature of the curve from which the curve changes direction.

In the graph shown for the quadratic function, it has minimum point as the graph opens upwards. So, the vertex is the minimum point of the curve.

The vertex of the graph is $(1,-2)$ .

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Help!!!!!! Please I have no idea what this is!!!

Semmy [17]

Answer:

33.49 cubic units

Step-by-step explanation:

$V_{sphere} = \frac{4}{3} \times \pi {r}^{3} \\ \\ V_{sphere} = \frac{4}{3} \times \pi {(2)}^{3} \\ \\ V_{sphere} = \frac{4}{3} \times \pi \times 8 \\ \\ V_{sphere} = \frac{32 \times 3.14}{3} \\ \\ V_{sphere} = \frac{100.48}{3} \\ \\ V_{sphere} = 33.4933333\\ \\ V_{sphere} \approx 33.49\: units^3$

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2 years ago

5x + 10 = 20

Andrei [34K]

To solve for x, we must first isolate the term containing x which in this problem is 5x.

Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.

On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.

Now we can finish things off by just dividing both sides of the equation by 5. On the left the 5's cancel and on the right, 10 divided by 5 is 2 so x = 2.

4 0

3 years ago

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0+ (2x + 1)

ElenaW [278]

$\displaystyle\lim_{x\to0^+}(2x+1)\cot x=\lim_{x\to0^+}\frac{2x+1}{\tan x}$

As $x\to0$ , the numerator approaches 1 while $\tan x\to0$ , but since $x\to0$ from above we have $\tan x>0$ , which suggests the limit is $+\infty$ .