Need helppppp asapppppppppp
1 answer:
You might be interested in
Answer:
<u>The function f(x)=a(x-h)² + k is the parabola with vertex:</u>
- (h, k)
If the vertex is in the second quadrant, the h < 0 and k > 0
It can open up or down, so a ≠0, it opens up if a > 0, opens down if a < 0
The axis of symmetry is the line parallel to y-axis and passing through the vertex, so it would be the line:
- x = h
<u>Now let's assume h = -5, k = 2, a = 1, then our function is:</u>
- f(x) = (x + 5)² + 2
The graph is attached and it opens up as a = 1 > 0
<u>The line of symmetry is </u>
- x = - 5
