The solutions to the given system of equations are x = 6 and y = -5
<h3>Simultaneous linear equations</h3>
From the question, we are to solve the given system of equations
The given system of equation is
4x+5y=-1
-5x-8y=10
Multiply the <u>first equation</u> by 5 and the <u>second equation</u> by 4
5× (4x+5y=-1)
4× (-5x-8y=10)
20x + 25y = -5
-20x - 32y = 40
------------------------
0x + (-7y) = 35
-7y = 35
y = 35/-7
y = -5
Substitute the value of y into the first equation to find x
4x + 5y = -1
4x + 5(-5) = -1
4x -25 = -1
4x = -1 +25
4x = 24
x = 24/4
x = 6
Hence, the solutions to the given system of equations are x = 6 and y = -5
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Answer:
The length of KH is 6 units and OH is 6.3 units.
Step-by-step explanation:
Given the figure with lengths LO=5 and OK=4. we have to find the length of OH and KH.
In ΔLOH
By Pythagoras theorem
→ (1)
In ΔKOH,
→ (2)
In ΔKHL,

Using eq (1) and (2), we get


⇒ 
⇒ 
Put the above value in eq 2, we get
⇒ KH=6 units.
For this case we must represent the following expression algebraically:
"eight more than the product of a number and two"
Let "x" be the variable that represents the unknown number
We have to:
the product of a number and two is represented as: 
Then, the full expression will be:

Thus, we use multiplication and addition.
ANswer:
Option C
16/10=1.6 so the smallest number of combos would be 1.