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gavmur [86]
3 years ago
9

A scientist wants to know if there is a meaningful difference between two groups of gels that grow bacteria. He randomly selects

five gels from each group, and counts the number of bacteria spots on each gel:
Group A: 9, 12, 13, 14, 17

Group B: 6, 5, 8, 13, 8

Find the mean and MAD of Group A and Group B.
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

Answer is in there^ couldn’t fit photos

Step-by-step explanation:

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X to the second - 6x+9=25 value of x
Cloud [144]

Answer:

-8/3 or -2.66666 or -2 2/3

Step-by-step explanation:

Move constant (+9) to the right side and change its sign (25 - 9)

Then subtract those numbers (=16)

Divide both sides by -6

3 0
3 years ago
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30 points pls someone answer
ipn [44]

Answer:

x = 8

Explanation:

f(x) = g(x)

Given:

  • f(x) = -20x + 11
  • g(x) = -19x + 3

solve:

-20x + 11 =  -19x + 3

-20x + 19x = 3 - 11

-x = -8

x = 8

4 0
2 years ago
PLZZZZZ HELP ME I'M GIVING BRAINLIEST
konstantin123 [22]

Answer:

d.13

Step-by-step explanation:

If you bring the 8 to the to the other side and you add to 5 you get 13. Also if you plug in the answer choices you should 13 since it makes the most sense. (13-8=5)

7 0
3 years ago
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A right rectangle prism is 6 cm by 14 cm by 5 cm what is the surface area of the right prism
NeX [460]

Answer:

\large\boxed{S.A.=368\ cm^2}

Step-by-step explanation:

The formula of a surface area of a rectagular prism:

S.A.=2(lw+lh+wh)

l - length

w - width

h - height

We have the dimensions 6cm × 14cm × 5cm. Substitute:

S.A.=2(6\cdot14+6\cdot5+14\cdot5)=2(84+30+70)=2(184)=368\ cm^2

8 0
3 years ago
Match each function with its inverse function. use function composition to determine your answers.
topjm [15]

QUESTION 1

\boxed {f(x) = 2x + 6 \to \: g(x) =  \frac{1}{2}x - 3 }

The reason is that:

g(f(x)) = 2( \frac{1}{2} x - 3) + 6

Expand:

g(f(x)) = x - 6+ 6

g(f(x)) = x

QUESTION 2

\boxed {f(x) =3 -  2x  \to \: g(x) =   - \frac{1}{2}(x - 3)}

The reason that

g(f(x)) =  -  \frac{1}{2} (3 - 2x - 3)

g(f(x)) =  -  \frac{1}{2} (- 2x )

g(f(x)) =x

QUESTION 3

\boxed {f(x) = \sqrt[3]{3x}+ 2 \to \: g(x) =   \frac{ {(x - 3)}^{3} }{3} }

The reason is that:

f(g(x)) =  \sqrt[3]{ \frac{3 {(x - 2)}^{3} }{3}  }  + 2

f(g(x)) =  x-2 + 2

f(g(x))=x

QUESTION 4

\boxed {f(x)=3\sqrt[3]{x + 2} \to \: g(x) = \frac{1}{27} {x}^{3} - 2}

The reason is that

f(g(x)) = 3 \sqrt[3]{ \frac{1}{27} {x}^{3}  - 2 + 2}

f(g(x)) = 3 \sqrt[3]{ \frac{1}{27} {x}^{3} }

f(g(x)) = 3 \times  \frac{1}{3} x

f(g(x)) =x

6 0
3 years ago
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