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3 years ago

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A scientist wants to know if there is a meaningful difference between two groups of gels that grow bacteria. He randomly selects

five gels from each group, and counts the number of bacteria spots on each gel:
Group A: 9, 12, 13, 14, 17

Group B: 6, 5, 8, 13, 8

Find the mean and MAD of Group A and Group B.

1 answer:

Mnenie [13.5K]3 years ago

4 0

Answer:

Answer is in there^ couldn’t fit photos

Step-by-step explanation:

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X to the second - 6x+9=25 value of x

Cloud [144]

Answer:

-8/3 or -2.66666 or -2 2/3

Step-by-step explanation:

Move constant (+9) to the right side and change its sign (25 - 9)

Then subtract those numbers (=16)

Divide both sides by -6

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Answer:

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Explanation:

f(x) = g(x)

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f(x) = -20x + 11

g(x) = -19x + 3

solve:

-20x + 11 = -19x + 3

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2 years ago

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konstantin123 [22]

Answer:

d.13

Step-by-step explanation:

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A right rectangle prism is 6 cm by 14 cm by 5 cm what is the surface area of the right prism

NeX [460]

Answer:

$\large\boxed{S.A.=368\ cm^2}$

Step-by-step explanation:

The formula of a surface area of a rectagular prism:

$S.A.=2(lw+lh+wh)$

l - length

w - width

h - height

We have the dimensions 6cm × 14cm × 5cm. Substitute:

$S.A.=2(6\cdot14+6\cdot5+14\cdot5)=2(84+30+70)=2(184)=368\ cm^2$

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3 years ago

Match each function with its inverse function. use function composition to determine your answers.

topjm [15]

QUESTION 1

$\boxed {f(x) = 2x + 6 \to \: g(x) = \frac{1}{2}x - 3 }$

The reason is that:

$g(f(x)) = 2( \frac{1}{2} x - 3) + 6$

Expand:

$g(f(x)) = x - 6+ 6$

$g(f(x)) = x$

QUESTION 2

$\boxed {f(x) =3 - 2x \to \: g(x) = - \frac{1}{2}(x - 3)}$

The reason that

$g(f(x)) = - \frac{1}{2} (3 - 2x - 3)$

$g(f(x)) = - \frac{1}{2} (- 2x )$

$g(f(x)) =x$

QUESTION 3

$\boxed {f(x) = \sqrt[3]{3x}+ 2 \to \: g(x) = \frac{ {(x - 3)}^{3} }{3} }$

The reason is that:

$f(g(x)) = \sqrt[3]{ \frac{3 {(x - 2)}^{3} }{3} } + 2$

$f(g(x)) = x-2 + 2$

$f(g(x))=x$

QUESTION 4

$\boxed {f(x)=3\sqrt[3]{x + 2} \to \: g(x) = \frac{1}{27} {x}^{3} - 2}$

The reason is that

$f(g(x)) = 3 \sqrt[3]{ \frac{1}{27} {x}^{3} - 2 + 2}$

$f(g(x)) = 3 \sqrt[3]{ \frac{1}{27} {x}^{3} }$

$f(g(x)) = 3 \times \frac{1}{3} x$

$f(g(x)) =x$

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3 years ago