The equation that can be used to represent total tickets sales is 2170 = 5s + 2f + 10a
<h3>Equation</h3>
let
- Number of students tickets = s
- Number of faculty tickets = f
- Number of alumni tickets = a
Expression for number of students tickets sold;
s = f + 15
Expression for number of faculty tickets sold;
f = 2a
Expression for number of alumni tickets sold;
f = 2a
a = f/2
- Cost of students tickets = $5
- Cost of faculty tickets = $2
- Cost of Alumni tickets= $10
- Total revenue = $2170
2170 = 5s + 2f + 10a
Learn more about equation:
brainly.com/question/4344214
#SPJ1
Answer:
-10x +4
Step-by-step explanation:
∠2 =∠1 which is 180° -65° =115<span>°
So </span>∠2=115<span>° </span>
1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))
The area of a triangle is equal to 1/2bh (one half base times height). Since this is a right triangle, the base and height are the two legs connected to the 90* angle. To find the values of these sides, we will use Pythagorean Theorem, root a squared plus b squared.
Short leg: <x(1),y(1)>
This leg can be seen as the hypotenuse of an invisible right triangle. The x value, x(1), is how far over the x value has gone from the origon at x=0. Imagine a leg alone the x-axis, going from (0,0) to (x(1),0). The y value of the point, y(1), works the same way. This leg will go from our previous mark at (x(1),0) to the point (x(1),y(1)). This shows that the short leg of the main triangle is the hypotenuse, with a height of y(1) and base of x(1). Pythagoreum Theorem shows that the length of this leg is equal to sqrt(x_1^2+y_1^2).
Long leg: <x(2), y(2)>
The same process works here, giving us sqrt(x_2^2+y_2^2).
Now for the area, we have the b and h values. Our equation reads 1/2sqrt(x_1^2+y_1^2)sqrt(x_2^2+y_2^2).
But we can simplify this (yay). The two square roots can be written together as sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))
So the correct answer is 1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))
Answer:
In the sciences, many times it is necessary to be able to interpret graphs as well as be able to graph certain equations. Often data is available in a graphical format and you must be able to extract the necessary information. Other times, it may be helpful to plot an equation in order to fully understand a problem. However, graphing can be difficult for some students. The format in this section is a little different. The first part will be simply showing what some special equations look like in graphical form and the second part will be a series of questions to help you understand graphs better.
Step-by-step explanation:
