Question

The probability that a student takes an English class and a math class is 0.084. The probability that a student takes an English class is 0.49. What is the probability that a student takes a math class given that the student is taking an English class?

Answer 1

We are given the probability of a student taking both classes of 0.084 and the problaity of taking english class of 0.49. The probability  that a student takes a math class given that the student is taking an English class is 0.084/0.49 equal to 0.17

Answer 2

Answer:

The probability that a student takes a math class given that the student is taking an English class $P(B/A)=0.17$        

Step-by-step explanation:

Given : The probability that a student takes an English class and a math class is 0.084. The probability that a student takes an English class is 0.49.

To find : What is the probability that a student takes a math class given that the student is taking an English class?

Solution :  

Let A be the student takes English class.

Let B be the student take Math class.

Probability that a student takes an English class and a math class is 0.084.

$P(A\cap B)=0.084$

The probability that a student takes an English class is 0.49.

$P(A)=0.49$

We have to find probability that a student takes a math class given that the student is taking an English class $P(A/B)$

Formula of conditional probability is

$P(B/A)=\frac{P(A\cap B)}{P(A)}$

Where B is the probability to find and A is the given condition.

$P(B/A)=\frac{0.084}{0.49}$

$P(B/A)=0.17$