Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
6x + 2
Explanation:
4 + -2 = 2 and x + 3x + 2x = 6x
Here is your answer to the question
4500(1.15)^5 = <span>9051 = From 1995 to 2000.
</span><span>9051(.96)^5 = 7380 = From 2000 to 2005.
</span>
7380 is your answer.
