Answer: Quality of service(QoS) is the parameter of the software development. This signifies about the management of the software resources,eliminating traffic or errors and evaluating the assurance about service quality of software.
There are several features that come under the quality of service feature to determine the software quality such as performance, scalability, service,scalability etc.If the software is evaluated positive on these factors then service quality is considered good which results in appropriate software development.
Answer:
customer service and support
Explanation:
-Loyalty programs for current customers refer to incentives companies provide to existing customers to encourage them to keep buying their products or services.
-Customer service and support refers to the assistance companies provide to their existing customers to help them solve issues or provide information about their current products or services and other options.
-Profitability for the company refers to actions that will increase the financial gains of the company.
-Acquisition of new customers refers to actions implemented to attract clients.
According to this, the answer is that this is a typical example of CRM that focuses on customer service and support because you call the company to get assistance with options to change your current products.
The other options are not right because the situation is not about incentives for the customer or actions the company implements to increase its revenue. Also, you are not a new customer.
I am pretty sure that the statement should be completed like this: <span>The control programs managing computer hardware and software perform the Job management function to control and prioritize tasks performed by the CPU. This king of programs is a part of operating system. Operating system is a set of software that helps to control and maintain computer resources like hardware and software.</span>
#include <stdio.h>
struct student {
char firstName[50];
int roll;
float marks;
} s[5];
int main() {
int i;
printf("Enter information of students:\n");
// storing information
for (i = 0; i < 5; ++i) {
s[i].roll = i + 1;
printf("\nFor roll number%d,\n", s[i].roll);
printf("Enter first name: ");
scanf("%s", s[i].firstName);
printf("Enter marks: ");
scanf("%f", &s[i].marks);
}
printf("Displaying Information:\n\n");
// displaying information
for (i = 0; i < 5; ++i) {
printf("\nRoll number: %d\n", i + 1);
printf("First name: ");
puts(s[i].firstName);
printf("Marks: %.1f", s[i].marks);
printf("\n");
}
return 0;
}
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Answer:
The program is as follows:
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int num1, num2, num3;
cin>>num1>>num2>>num3;
cout << fixed << setprecision(2);
cout<<(num1 + num2 + num3)/3<<" ";
cout<<num1 * num2 * num3<<" ";
return 0;
}
Explanation:
This declares three integer variables
int num1, num2, num3;
This gets input for the three integers
cin>>num1>>num2>>num3;
This is used to set the precision to 2
cout << fixed << setprecision(2);
This prints the average
cout<<(num1 + num2 + num3)/3<<" ";
This prints the product
cout<<num1 * num2 * num3<<" ";