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gladu [14]
3 years ago
11

Relationship between application system.and database​

Computers and Technology
1 answer:
RideAnS [48]3 years ago
3 0

Explanation:

there is a very close relationship between DBMS and application programs the application programs provide the user-interface to send request to DBSM and to receive processed results from DBMS processes that request and return the results to the application program and also controls and manages the database

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Who is the first British in Europe ​
Vera_Pavlovna [14]

Answer:

"The British" are people statically from Great Britain in the UK.

7 0
3 years ago
Question: 4/8
Gemiola [76]

The generated test cases for the function assuming another developer coded the function is given below in a C++ program.

<h3>THE CODE</h3>

#include <iostream>  

#include <iomanip>

#include <string>

using namespace std;

// define the data type "triangletype" with {values}

enum triangleType { scalene, isosceles, equilateral, noTriangle };

// Prototype function which returns the position of triangleType{value}

// Example: Scalene = 0, isosceles = 1, etc. These are zero indexed.

triangleType triangleShape(double a, double b, double c);

// Prototype function which takes the integer value of the

// triangle type and outputs the name of triangle

string shapeAnswer(int value);

int main() {

   double inputA;

   double inputB;

   double inputC;

   cout << "To determine whether a triangle is either:" << endl;

   cout << setw(50) << " - Scalene" << endl; // Unequal in length

   cout << setw(52) << " - Isosceles" << endl; // Two sides equal length

   cout << setw(54) << " - Equilateral" << endl; // All sides equal

   cout << setw(57) << " - Not a triangle" << endl;

   cout << "Enter side A: ";

   cin >> inputA;

   cout << "Enter side B: ";

   cin >> inputB;

  cout << "Enter side C: ";

   cin >> inputC;

   cout << "The triangle is " << shapeAnswer(triangleShape(inputA, inputB, inputC)) << endl;

}

triangleType triangleShape(double a, double b, double c) {

   triangleType answer;

   if ( c >= (a + b) || b >= (a + c) || a >= (b + c) ) {

       answer = noTriangle;

   }

   else if (a == b && b == c) {

       answer = equilateral;

   }

   // Test the 3 options for Isosceles equality

   else if ( (a == b) && (a != c) || (b == c) && (b != a) || (a == c) && (a != b) ) {

       answer = isosceles;

   }

   else {

       answer = scalene;

   }

   return answer;

}

string shapeAnswer(int value) {

   string answer;

  switch (value) {

   case 0:

       answer = "Scalene";

       break;

   case 1:

       answer = "Isosceles";

       break;

   case 2:

       answer = "Equilateral";

       break;

   case 3:

       answer = "Not a triangle";

       break;

   default:

       break;

   }

   return answer;

}

Read more about C++ programs here:

brainly.com/question/20339175

#SPJ1

8 0
2 years ago
Given the declarations struct BrandInfo { string company; string model; }; struct DiskType { BrandInfo brand; float capacity; };
Nonamiya [84]

Answer:

Type of myDisk.brand is BrandInfo.

Explanation:

4 0
3 years ago
Computer science;
leonid [27]

Answer:

Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).

Explanation:

Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).

3 0
3 years ago
A company ABC asked you to design a simple payroll program that calculates and employee's weekly gross pay, including any overti
julsineya [31]

Answer:

<em>C++.</em>

#include <iostream>

using namespace std;

////////////////////////////////////////////////////////////////

int main() {

   int weekly_hours = 0;

   int hourly_rate;

   float gross_pay = 0;

   cout<<"Enter weekly hours worked: ";

   cin>>weekly_hours;

   

   cout<<"Enter hourly rate: ";

   cin>>hourly_rate;

   

   cout<<endl;

   ////////////////////////////////////////////////

   if (weekly_hours > 40) {

       gross_pay = (weekly_hours*hourly_rate) + ((weekly_hours*hourly_rate)*0.5);

   }

   else

       gross_pay = weekly_hours*hourly_rate;

       

   cout<<"Weekly gross pay: $"<<gross_pay;

   ////////////////////////////////////////////////

   return 0;

}

3 0
3 years ago
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