Answer:
Step-by-step explanation:
x-7y = -49
i) move x to the right-hand side and change its sign
-7y = -49-x
ii) change the signs on both sides of the equation
7y = 49+x
iii) divide both sides of the equation by 7
iv) use the commutative property to reorder the terms
* commutative property: a+b = b+a
Take 12 and divide it by 3 to get the number of slices per quarter. Then multiply the answer you got by four. The answer is 16.
The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
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We must follow order of operations rules (PEMDAS).
Thus, mult. and div. must be carried out before addn. and subtrn.
Calculate the quotient of (-2/5) and (4/5). In other words, divide (4/5) into (-2/5). Invert (4/5) and multiply:
(-2/5)(5/4) = -1/2
Then we have, in place of the original expression, the following expression:
-3/4 - 1/2 + (2 1/2).
Rewriting 2 1/2 as an improper fraction and elim. the parentheses yields:
-3/4 - 2/4 + 5/2, or -3/4 - 2/4 + 10/4, since the LCD is 4.
This yields 5/4 (answer)
Answer:
false it can be in any order but must be according to the set of data