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3 years ago

You use 4 gallons of water on 14 plants in your garden.

Mathematics

2 answers:

GrogVix [38]3 years ago

4 0

Answer:

35 plants

Step-by-step explanation:

For this case we can make the following rule of three:

4 gallons --------------> 14 plants

x --------------------------> 35 plants

From here, we clear the value of x.

We have then:

therefore, 10 gallons are needed to irrigate 35 plants.

Answer:

it will take 10 gallons to water 35 plants

Reptile [31]3 years ago

4 0

Answer: 10 gallons

4 gallon/14 plants= x gallons/ 35 plants

35*4=140/14=x

x=10 gallons

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First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

3 years ago

Please guys help me with this. I will give you brainliest. please ❤❤

yawa3891 [41]

Answer:

. ........

Step-by-step explanation:

may i know were is the question??

lol

4 0

3 years ago

Read 2 more answers

75 people to 25 people

Nat2105 [25]

Percent decrease { (original number - new number) / original number....x 100

percent decrease : (75 - 25) / 75....x 100
50 / 75...x 100
0.666 x 100
66.6% decrease <==not sure if u need it rounded ?

4 0

3 years ago

Find the surface area of a rectangular prism with base 4 m by 5 m and height 8 m.

Andre45 [30]

Answer:

Step-by-step explanation:

surface area=area of sides +area of top and bottom

=2(4+5)×8+2×(4×5)

=2[(9×8)+20]

=2[72+20]

=2×92

=184 m²

4 0

3 years ago

Read 2 more answers

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0

2 years ago