Answer:
0.58 = 58% probability she passes both courses
Step-by-step explanation:
We can solve this question treating the probabilities as a Venn set.
I am going to say that:
Event A: She passes the first course.
Event B: She passes the second course.
The probability she passes the first course is 0.67.
This means that 
The probability she passes the second course is 0.7.
This means that 
The probability she passes at least one of the courses is 0.79.
This means that 
a. What is the probability she passes both courses
This is 
.
We use the following relation:
So
0.58 = 58% probability she passes both courses
Answer:
D
Step-by-step explanation:
a is false since x could be 0.
b is easy to check, just plug numbers in, and we can see that it's false(you would get 0+0=1 and -0-0=-1 once plugged in)
c is also easy to check, just plot the line or simplify the first equation. since (2x+2y)/2=4/2 is also x+y=2, the second equation is also x+y=2, so it must have infinitely many solutions.
d must be true due to process of elimination but let's check to make sure.
7y=14x, divide both sides by 7 to get y=2x and since they're the same equation it must mean that they have infinitly many solutions and we can see that it is correct
Answer:
angle ERT = angle YUP
Step-by-step explanation:
Answer:
Step-by-step explanation:
5x-3
We know that you have 9 quarters
We also know that you have 21 pennies
Probability is represented as "determined factor" / total
First, we need to find the total amount of possibilities. This means that you have to add 21 and 9
21 + 9 = 30
We want to know the probability of picking a penny out of the hat, so you would represent this as:
21/30
To turn it into a percent, divide 21 by 30.
21 ÷ 30 = 0.7
0.7 is equivalent to 70% as a percent
This means that you will have a 70% chance of picking a penny out
Answer: 70%
