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2 years ago

15

"Two planes leave the airport at the same time. Plane 1 travels just 9 miles east from

1 answer:

Vika [28.1K]2 years ago

8 0

The answer is 41 miles

Imagine the diagonal distance is called c
Using Pythagorean theorem 40^2 + 9^2 = c^2
1600 + 81 = c^2
The square root of 1681 is 41
So c = 41

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PLEASE HELP I GIVE THANKS

Levart [38]

A=(-6,-2)
B=(6,2)

$\sqrt{[(6-(-6)]^2+[(2-(-2)]^2} = \sqrt{12^2+4^2} = \sqrt{16} =4 \sqrt{10}$

5 0

2 years ago

The probability distribution for a random variable x is given in the table. -5 -3 -2 0 2 3 Probability .17 .13 33 16 11 10 Find

IgorLugansk [536]

Answer:

0.79

Step-by-step explanation:

add up the probability that is less than or equal to 0, which is 0.17+0.13+0.33+0.16 = 0.79

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2 years ago

What is the length of segment AB?<br> Consider the diagram.<br> 7,9,18,25

Mrrafil [7]

Answer:

9

Step-by-step explanation:

It is congruent to the other side.

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3 years ago

Susan drove to visit a friend. She drove 345

padilas [110]

Answer:

$Average\ Speed = 60 mi/hr$

Step-by-step explanation:

Given

$Distance = 345\ miles$

$Time = 5\ hours\ 45\ minutes$

Required

Determine the average speed

This is calculated as thus:

$Average\ Speed = \frac{Distance}{Time}$

Convert time to hour:

$Time = 5\ hours\ 45\ minutes$

$Time = 5\ hours + \frac{45}{60}\ hour$

$Time = 5\ hours + \frac{3}{4}\ hour$

$Time = \frac{20 + 3}{4}\ hours$

$Time = \frac{23}{4}\ hours$

$Time = 5.75\ hours$

$Average\ Speed = \frac{Distance}{Time}$

$Average\ Speed = \frac{345}{5.75}$

$Average\ Speed = 60 mi/hr$

7 0

2 years ago

What is the vertex of the quadratic function f(x)=x2+6x+16? Write your answer

Olenka [21]

Answer:

The vertex of the quadratic function is:

$(x_{v}, y_{v})=\left(-3,\:7\right)$

Step-by-step explanation:

Given the function

$f\left(x\right)=x^2+6x+16$

As the vertex of the form $y=ax^2+bx+c$ is defined as:

$x_v=-\frac{b}{2a}$

As the quadratic function of parabola params are

$a=1,\:b=6,\:c=16$

so

$x_v=-\frac{b}{2a}$

$x_v=-\frac{6}{2\cdot \:1}$

$x_v=-3$

Putting $x_v=-3$ to determine $y_v$

$y_v=\left(-3\right)^2+6\left(-3\right)+16$

$y_v=3^2-18+16$

$y_v=9-2$

$y_v=7$

Therefore, the vertex of the quadratic function is:

$(x_{v}, y_{v})=\left(-3,\:7\right)$

5 0

3 years ago