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3 years ago

Pls help me, here's the screenshot and see how y'all can help me

Mathematics

2 answers:

Vladimir79 [104]3 years ago

7 0

<h3>The y intercept is -1</h3>

We can say that the y intercept is at the location (0,-1)

This is where the graph crosses the vertical y axis. This is 1 unit below the origin.

This is assuming each tickmark on the grid represents 1 unit.

MAXImum [283]3 years ago

7 0

Answer:

The y- intercept is (0,-1)

Step-by-step explanation:

A y- intercept is when a point intercepts (crosses) the y- axis. Since the dot does not cross the x- axis, that point will be 0. It is below the y- axis, meaning it will be -1.

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Find the product: (x² - x + 1)(2x² + 3x + 2).

Tresset [83]

Answer:

(2x^3-2x^2-12x) is the required product.

Step-by-step explanation:

The given equation is:

2x(x-3)(x+2)

Solving the above given equation, we get

=(2x^2-6x)(x+2)

which can be written as:

=(2x^3-6x^2+4x^2-12x)

Solving the like terms, we get

=(2x^3-2x^2-12x)

which is the required product of the given expression.

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3 years ago

The half life of a radioactive kind of cadmium is 14 years. How much will be left after 28 years, if you start with 72 grams of

nlexa [21]

Answer:

18 grams

Step-by-step explanation:

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3 years ago

The lunch choices last Friday were mushroom or pepperoni pizza. The cafeteria made 8

Anna11 [10]

Answer:

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2 years ago

Read 2 more answers

What graph is a function of x

Nookie1986 [14]

Show me the picture for I can help u

3 0

3 years ago

Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col

natali 33 [55]

Answer:

$\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

$\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]$

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

$A^{-1}$ = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = $\left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]$

$A^{-1}$ = $\frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right]$ = $\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

4 0

3 years ago