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rusak2 [61]
3 years ago
11

Which inequality goes with “at least” ? A. X > B. X < C. X <_ D. X >_

Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

C because ≤ means less than or equal to.

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Which of the following equations is equivalent to x - y = 5?
Masja [62]

Answer:

6x-6y=30

Step-by-step explanation:

<u><em>The complete options are</em></u>

a) x - 2y = 30

b) 4x - 3y = 30

c) 3x - 4y = 30

d) 6x - 6y = 30

The given equation is

x-y=5

<u>Verify option d</u>

we have

6x-6y=30

Divide by 6 both sides

(6x-6y)/6=30/6

\frac{6x}{6}-\frac{6y}{6}=\frac{30}{6}

x-y=5

therefore

x-y=5  and 6x-6y=30 are equivalent

3 0
3 years ago
Dylan and three of his friends went to dinner at Texas Roadhouse. The cost of the meal was $41.56. If they split the bill equall
Volgvan
Each person would pay 10.39 a piece
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3 years ago
Calculate the slope of a line ​
jeka94
M=-1/2 because you do y1-y2 over x1-x2 and end up with 2/-4 but simplified is -1/2
6 0
3 years ago
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I really need help. Find a. Round to the nearest tenth.
valina [46]

Answer:

a ≈ 1.8

Step-by-step explanation:

a / sin (180 - 105 - 15)° = 2 /sin 105°

a = (2 /sin 105°) x sin 60°

a = (2 / 0.97) x 0.87

a = 1.79    (≈ 1.8)

6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
pashok25 [27]

Answer:

Graph A → y=√x.

Graph B → y=(√x) - 1.

Graph C → y=√(x-1).

Graph D → y= -√x.

Graph E → y= -√(x-1)

Step-by-step explanation:

The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.

The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.

The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)

The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)

In the options you have two times the function y=√x. I assume that's a mistake. The graph 'B' corresponds to y = (√x) - 1

4 0
3 years ago
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