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3 years ago

Which is NOT true about a direct proportion?

Mathematics

1 answer:

madam [21]3 years ago

8 0

The person at the top is correct.

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Given that MTW = CAD, which segments are corresponding parts of the congruent triangles?

VikaD [51]

Answer: MW = CD

Explanation: It would be this way because if you wrote the triangles out, MW would be in the same place as CD, making them corresponding.

6 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Mr.varela bought a block of fudge that weighed 3/4 of a pound. He cut the fudge into 2 equal pieces. What was the weight of each

OleMash [197]

To do this, multiply 3/4 by 1/2 and you end up with 3/8 lb. or 0.375 lb.

6 0

3 years ago

True or false: Weight which is less than 85% of what is considered normal for age and height is a main characteristic of bulimia

alex41 [277]

Answer:

True

Step-by-step explanation:

5 0

3 years ago

What is y=7/4x+6 if the input was 53

Shkiper50 [21]

7/4(53) + 6
92.75 + 6

98.75

5 0

3 years ago