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3 years ago

Which equation could you use to find 15 ÷ 3? 15 + 3 = 18 18 – 3 = 15 3 × 5 = 15 30 ÷ 2 = 15

Mathematics

1 answer:

kondor19780726 [428]3 years ago

4 0

3 x 5 = 15 because the opposite of dividing is multiplying

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A school is arranging a field trip to the zoo. The school spends 784.52 dollars on passes for 42 students and 2 teachers. The sc

zvonat [6]

The lunches cost 8.79 dollars per student and guessing that the teacher and student tickets cost the same, the passes are 17.83 dollars.

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3 years ago

What is the x-intercept and y-intercept of the linear equation 3x-6y=2

sukhopar [10]

Answer:

The x-intercept is 2/3 and the y-intercept is -1/3

Step-by-step explanation:

In order to find this, we need to note that the x-intercept is the value of x, when y = 0. So we plug in y = 0 and see what the x value is.

3x - 6y = 2

3x - 6(0) = 2

3x = 2

x = 2/3

The y-intercept is the opposite. It is the y value when x = 0. So we do the same with the other term.

3x - 6y = 2

3(0) - 6y = 2

-6y = 2

y = -2/6

y = -1/3

8 0

3 years ago

How do i answer this??

tatyana61 [14]

Answer:

y=29

Step-by-step explanation:

if x=5. 5x5+4. 5x5=25. 25+4=29

8 0

2 years ago

Read 2 more answers

How do I differentiate this?

disa [49]

Answer:

$\frac{8}{\left(-x+2\right)^2}$ & $x = 1, x = 3$

Step-by-step explanation:

I'm sure you are familiar with the product rule,

If y = u*v => dy/dx = u * dv/dx + v * dy/dx <----- product rule

In this case:

$u=3x+2,\:v=\left(2-x\right)^{-1},\\=>\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

Now remember the sum rule:

$\frac{d}{dx}\left(3x+2\right) = \frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(2\right),\\\frac{d}{dx}\left(3x\right) = 3,\\\frac{d}{dx}\left(2\right) = 0\\\frac{d}{dx}\left(3x+2\right) = 3$

For this second bit we apply the chain rule:

$\frac{d}{dx}\left(\left(2-x\right)^{-1}\right) = -\frac{1}{\left(2-x\right)^2}\frac{d}{dx}\left(2-x\right),\\\frac{d}{dx}\left(2-x\right) = -1,\\\\=> -\frac{1}{\left(2-x\right)^2}\left(-1\right)\\=> \frac{1}{\left(2-x\right)^2}$

If we substitute these values back into the expression... $\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

...we get the following:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)$

The rest is just pure simplification:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)\\= \frac{3}{-x+2}+\frac{3x+2}{\left(-x+2\right)^2}\\= \frac{3\left(-x+2\right)}{\left(-x+2\right)^2}+\frac{3x+2}{\left(-x+2\right)^2}\\\\= \frac{3\left(-x+2\right)+3x+2}{\left(-x+2\right)^2}\\\\= \frac{8}{\left(-x+2\right)^2}$

Now let's equate this to equal 8 for the second bit and solve for x:

$\frac{8}{\left(-x+2\right)^2}=8,\\\frac{8}{\left(-x+2\right)^2}\left(-x+2\right)^2=8\left(-x+2\right)^2,\\8=8\left(-x+2\right)^2,\\\left(-x+2\right)^2=1,\\x = 1, x = 3$

4 0

3 years ago

What is the circumference of quadrilateral ABED in cm?

Natasha2012 [34]

the perimeter of quadrilateral ABED is 36.

<h3 /><h3>What is circumference?</h3>

A circumference is the total distance around a plane shape. Another name for circumference is called perimeter

To calculate the circumference of the quadrilateral, we use the formula below.

Formula:

Peri. of ABED = /AB/+/BE/+/ED/+/DA/............. Equation 1

From the Diagram,

Given:

/AB/ = /DC/ = 8 cm,
/BE/ = 2×/DA/ = 2×6 = 12 cm
/ED/ = √(6²+8²) = √(36+64) = √100 = 10 cm
/DA/ = 6 cm

Substitute these values into equation 1

Peri. of quadrilateral ABED = 8+12+10+6
Peri. of quadrilateral ABED = 36 cm

Hence, the perimeter of quadrilateral ABED is 36.

Learn more about circumference here: brainly.com/question/20489969

#SPJ1

4 0

1 year ago