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4 years ago

Which equation could you use to find 15 ÷ 3? 15 + 3 = 18 18 – 3 = 15 3 × 5 = 15 30 ÷ 2 = 15

Mathematics

1 answer:

kondor19780726 [428]4 years ago

4 0

3 x 5 = 15 because the opposite of dividing is multiplying

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

3 years ago

How would you solve the equation 4x = 100?

LenKa [72]

Answer:

Step-by-step explanation:

4x = 100

x = 100/4

x = 25

3 0

3 years ago

Read 2 more answers

Which statements are true? Select three options.<br><br> You can use for reference ;)

Dovator [93]

The answers are A,C,&E

3 0

2 years ago

Can some one please help me <br> will give 94 points for it

NNADVOKAT [17]

You can solve this by using "similar triangles".

In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.

You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
$\frac{AC}{BC} = \frac{DF}{EF}$
Substitute for the values of AC, BC, DF and EF:
$\frac{x}{4} = \frac{11}{8} \\ \\ 8x = 4 \times 11 \\ \\ x = \frac{44}{8}$
$x = 5.5 \: units$
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
$\frac{AB}{BC} = \frac{DE}{EF}$
Substitute for the values and solve:
$\frac{3}{4} = \frac{y}{8}$
$4y = 24 \\ \\ y = 6 \: units$

We have the value x to be 5.5 units and y to be 6 units.

7 0

3 years ago

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Algebra: Solve for x

Irina-Kira [14]

Answer:

Step-by-step explanation:

6-x/2=4

6-x=4*2

6-x=8

x=2

5 0

3 years ago

Read 2 more answers