<span>Polydactyly in its most common form, is an autosomal dominant mutation. Let's represent the mutation as P and the normal state as +. Thus, if both parents are heterozygous (P+), both would have the mutation (and thus have six fingered). They have 3/4 chances of having a child with the extra digit, 1/4 normal. </span>
The grass carp is herbivorious
A heterozygous cat has a genotype Hh
A hairless cat has a genotype hh
When crossed, the results could be any of the following:
Hh (with hair)
hh (hairless)
There is a 50:50 chance or 1: 1 ratio that the offspring will have hair.
Answer:
do you have a chart of choices or no?
I am pretty sure the answer is increase and increase. Because enzymes are affected by changes in pH. The most favorable pH value - the point where the enzyme is most active - is known as the optimum pH. Extremely high or low pH values generally result in complete loss of activity for most enzymes.
