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Let the number of nickels be = x
Let the number of dimes be = d
Let the number of quarter be = n
Given is, she has twice as many dimes as quarters
d=2n or n = 0.5d
She has two less quarters than nickles.
n= x-2 or
x= n+2
Total values of coins is = $2.60
Now replace x with (n+2) and d with 2n
Now x=n+2 ; x=5+2 = 7
d=2n ; d=2(5) = 10
Hence, Elina has 7 nickels, 10 dimes and 5 quarters.