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VikaD [51]
2 years ago
13

When C++ is working with an operator, it strives to convert operands to the same type. This is known as

Computers and Technology
1 answer:
ziro4ka [17]2 years ago
7 0

Answer:

The answer is "Option B"

Explanation:

Conversion of type is a way of changing an entity from one data type to another. It is used to make the variable process properly by a function in computer coding.  

In the C++ language, the result of the multitype value added or any other option is the result between those variables as a large type at that time, that's why choice b is correct.

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When you tell an acquaintance your telephone number, you do not recite the digits one by one at a constant rate, as in "3, 3, 7,
yKpoI14uk [10]

Answer:

chunking and short-term is the correct answer of this question.

Explanation:

chunking is a strategy to enhance a short-term memory.

Chunking is an method used to separate larger numbers that can not be psychologically separated.Chunking is the grouping of words in one sentence into short, important phrases. A chunk is the material segment that is used in many graphical formats, such as PNG etc.

Short-term memory is the knowledge a person is considering or is conscious of. This is also called healthy or main memory.

3 0
3 years ago
Which of these is not one of the main parts of an email?
pav-90 [236]
The header is not a main part of the email. 
3 0
3 years ago
Read 2 more answers
The input nums is supposed to be an array of unique integers ranging from 1 to nums.length (inclusive). However, there is a mist
Elden [556K]

The program is an illustration of loops.

Loops are used to perform repetitive and iterative operations.

The program in Python where comments are used to explain each line is as follows:

#This intializes the list

nums = [5,4,4,2,1]

#This gets the length of the list

size = len(nums)

#This iterates through the list

for i in range(size):

   #The following if condition determines the repeating number

   if nums[abs(nums[i])-1] > 0:

       nums[abs(nums[i])-1] = -nums[abs(nums[i])-1]

   else:

       repeating = abs(nums[i])

   #The following if condition determines the missing number

   if nums[i]>0:

       missing = i + 1

   

#This calculates and prints the sum of the missing and the repeating numbers

print(repeating+missing)

Read more about similar programs at:

brainly.com/question/13549861

6 0
3 years ago
What is the fifth and final stage in the process of media production?
Monica [59]

Answer:54

Explanation:

8 0
3 years ago
The length, height, and width of a cube are 10, 7, and 5 cm respectively. Write a program that calculates the volume, perimeter,
RideAnS [48]

Answer:

// code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int length=10,height=7,width=5;

   // find the volume of

   int vol=length*height*width;

   // find the surface area

   int sa=2*(length*width+length*height+height*width);

   // find the perimeter

   int peri=4*(length+width+height);

   // print the volume

   cout<<"Volume is: "<<vol<<" cm^3."<<endl;

   // print the surface area

   cout<<"Surface area is: "<<sa<<" cm^2."<<endl;

   // print the perimeter

   cout<<"Perimeter is: "<<peri<<" cm."<<endl;

return 0;

}

Explanation:

Declare and initialize length=10, width=5 and height=7.calculate volume by multiply length, width and height and assign to variable "vol".Then find the surface area as 2*(length*width+length*height+height*width) and assign it to variable "sa".Then find the perimeter as 4*(length+width+height) and assign to variable "peri". Print the volume, perimeter and surface area.

Output:

Volume is: 350 cm^3.

Surface area is: 310 cm^2.

Perimeter is: 88 cm.

8 0
3 years ago
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