Answer:
professional integrity
Explanation:
The work he is doing is comes under the violation of professional integrity. Because professional integrity is the set of ethics that should be followed by the employ. These ethics includes honesty, loyalty and dependability.
Answer: Suboptimization is referred to as a term that has been approved for common policy mistake. It usually refers to the practice of concentrating on a single component of a whole and thus making changes which are intended towards improving that component and also ignoring its effects on other components.
Answer:
The answer is "Always true
"
Explanation:
Following are the program to this question:
#include <iostream>//header file
using namespace std;
int main()//main method
{
bool x=true;//defining bool variable x and assign value
bool y=false;//defining bool variable y and assign value
if(!(x || y) || (x || y))//use given condition with if block
{
cout<<"True";//print true message
}
else//defining else block
{
cout<<"false";//print false message
}
return 0;
}
In the above code two bool variable is declared, that hold ture and false, and used in the given expression with the condition statement, that checks the given value. In the code the logical gate OR gate that always print the true value.
Answer:
Check the explanation
Explanation:
Going by the question above,there are 2 routers in a sequence amid Host A and Host B and using store-and-forward routing.
So that time would conprise of both propagation delay and transmission time
Propagation delay is nothing but the time taken for traveling.
Transmission delay is the amount of delay time from the beginning to end of transmission)
Now,
Propagation delay = distance traveled / speed of propagation
= 161200 / 2.7 *108 = 59703703.70 * 10-8 mili sec
Transmission delay:
= packet size / bandwidth
= 4 / (9.1 * 1024) = 4.2925 * 10-1 mili sec
Let us assume routers have zero (0) processing time
total time = Transmission delay by host A + Transmssion delay by router1 + Transmssion delay by router2 + propagation time
= 3 * ( 4.2925 * 10-1 ) + (59703703.70 * 10-8)
= 1.28775 + 0.5970370370 ms
= 1.884787 ms
