Answer:
In order to maximize the profit, should be produced 200 software program and 235 video games per week
Step-by-step explanation:
Let
x ------> the number of software program
y -----> the number of video games
we know that
-----> inequality A
-----> inequality B
-----> inequality C
Using a graphing tool
The solution is the shaded area between the positive values fo x and y
see the attached figure
The vertices of the shaded area are
(0,0),(0,300),(135,300),(200,235),(200,0)
The profit function is equal to
![P=50x+35y](https://tex.z-dn.net/?f=P%3D50x%2B35y)
Substitute the value of x and the value of y of each vertices in the profit function
For (0,300) ----- ![P=50(0)+35(300)=\$10,500](https://tex.z-dn.net/?f=P%3D50%280%29%2B35%28300%29%3D%5C%2410%2C500)
For (135,300) ----- ![P=50(135)+35(300)=\$17,250](https://tex.z-dn.net/?f=P%3D50%28135%29%2B35%28300%29%3D%5C%2417%2C250)
For (200,235) ----- ![P=50(200)+35(235)=\$18,225](https://tex.z-dn.net/?f=P%3D50%28200%29%2B35%28235%29%3D%5C%2418%2C225)
For (200,0) ----- ![P=50(200)+35(0)=\$10,000](https://tex.z-dn.net/?f=P%3D50%28200%29%2B35%280%29%3D%5C%2410%2C000)
therefore
In order to maximize the profit, should be produced 200 software program and 235 video games per week