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IrinaVladis [17]
3 years ago
15

Using the distributive property, rewrite this equation and put the correct numbers in place of the blanks.

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0

Answer:

There's no equation. You must've forgotten to put the file in the question.

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jek_recluse [69]
Answer: X = thirty-six

8 0
3 years ago
Two trains leave stations 252 miles apart at the same time and travel toward each other. One train travels at 80 miles per hour
Svetlanka [38]
First things first, distance = speed x time
So let's have "t" represent the time by both trains.
The first train shall be Train A and the other becoming Train B, so now we have Train A going 80t miles and Train B going 100t miles.


If two trains head toward each other, they will have traveled a total of 252 miles. The faster train will have traveled further (Train B), so the meeting point will be closer to the slower train's starting point (Train A).

So now we do 80t + 100t = 252
Which becomes 180t = 252
And by diving 252 by 180, you'll get that t is 1.4
This would mean they would meet at one hour and 24 minutes.
4 0
3 years ago
What is 2A- 3B, if A =<br> 12-13].and-[ -4 -2]
Liono4ka [1.6K]

Answer:

0

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Polygon ABCDE is reflection to produce polygon A’B’C’D E’. What is the equation for the line of reflection
lina2011 [118]

Answer:

D Hb=HB

Step-by-step explanation:

i'm pretty sure  thats the awnser

3 0
3 years ago
Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

8 0
3 years ago
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