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Dima020 [189]
3 years ago
9

Find the length of an arc of a circle with radius 12 cm if the arc subtends a central angle of 30°

Mathematics
2 answers:
german3 years ago
7 0
Formula for arc lenght:
l =  \frac{ \alpha }{360} 2r\pi
Insert given data:
l =  \frac{30}{360} \times  2 \times 12cm \times \pi
l = 2\pi  = 6.28cm

masya89 [10]3 years ago
6 0

Answer:

Let s be the length of the arc subtending an angle \sf{\theta}^{c} at the centre of a circle of radius r.

<u>Then</u><u>,</u><u> </u>

\\  \theta \:  =  \sf \:  \frac{s}{r} \\

Here,

  • r = 12 cm.
  • ∅ = 30°

\\  \implies \sf \:  \bigg(30 \times  \frac{\pi}{180}  \bigg) {}^{c}  \\  \\  \\  \implies \sf \blue{  \bigg({ \frac{\pi}{6} } \bigg)^{c}  } \\

<u>There</u><u>fore</u><u>,</u><u> </u>

\\  \theta =  \sf \:  \dfrac{s}{r}  \\  \\  \\  \implies \sf \:  \frac{\pi}{6}  =  \frac{s}{12}  \\  \\  \\  \implies \sf \red{s =  \frac{12\pi}{6} cm. }   \\

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25 less than x <br><br> Pls help anyone
konstantin123 [22]

Answer:

If you are looking for an equation, then it would be 25 < x.

Step-by-step explanation:

3 0
3 years ago
A boy is mowing a rectangular lawn 40ft long and 30ft wide. He has cut all of it except for a rectangle that is 20ft long and 15
sergejj [24]

Answer:

1/4

Step-by-step explanation:

Find the area of the full rectangle:

=> 40 x 30 = 1200

Find the area of the uncut part:

=> 20 x 15

=> 300

Make these numbers as a fraction.

=> 300 / 1200

=> 3/12

=> 1/4

So, 1/4 part remains uncut.

7 0
3 years ago
Read 2 more answers
Write each fraction as an expression using exponent other than -1
Sauron [17]
No no answer for that
6 0
4 years ago
Principle 400 at rate of 5% is
Juli2301 [7.4K]

Answer:

20

Step-by-step explanation:

do 5% of 400 which gives you 20 for your answer

8 0
4 years ago
ONLY SERIOUS ANSWERS!!!! 25 POINTS
AveGali [126]

Answer:

FD≈25.94.. rounded = 26

Step-by-step explanation:

FD²=12²+(4x+11)²

FD²=144+16x²+88x+121

FD²=265+16x²+88x

also

FD²=12²+(13x-16)²

FD²=144+169x²-416x+256

FD²=400+169x²-416x

thus

265+16x²+88x = 400+169x²-416x

16x²-169x²+88x+416x+265-400 = 0

-153x²+504x-135 = 0

we will solve this quadratic equation by suing the quadratic formula to find x

x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)

x=(-504±\sqrt{504^{2}-4(-153)(-135) })/2(-153)

x=(-504±\sqrt{254016-82620 })/-306

x=(-504±\sqrt{171396})/-306

x=(-504±414)/-306

x=(-504+414)/-306 and x=(-504-414)/-306

x=-90/-306 and x=-918/-306

x= 5/17 , 3

substituting x by the roots we found

check for 5/17:

4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..

13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..

check for 3:

4x+11 = 4×3+11 = 12+11 = 23

13x-16 = 13×3-16 = 23

thus 3 is the right root

therfore

ED=23 and CD=23

FD²=FE²+ED² or FD²=FC²+CD²

FD²=12²+23²

FD²=144+529

FD²=673

FD=√673

FD≈25.94.. rounded = 26

5 0
3 years ago
Read 2 more answers
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