10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
Answer:
The poultry house must have to be well ventilated.
Ensure sufficient entrance of sunlight and fresh air inside the house.
It would be better if the house become situated north to south faced.
The proper distance of one house to another house is about 40 feet.
Clean the house properly before keeping the birds inside the poultry house.
Make a deep liter and keep it dry and clean always.
Wooden and rice bran can be used for making liter.
Keep feed and feeding equipment in proper distance inside the poultry house according to the number and demand of poultry birds.
The poultry house and all equipment must have to be free from virus, parasites and germs.
Build the poultry house in such a place where all the poultry birds are free from all types of wild animals and other predators.
The poultry housing area will be free from loud sound/sound pollution.
Make the poultry house in quite and calm place.
It would be better if the house located in an open air place.
However, to be successful in poultry farming the producers must have to be aware in making the poultry house. Be sure that all necessary equipment and facilities are available inside the poultry house.
Explanation:
The answer is C. (0,1). I believe.
voltage difference is the push that causes charges to flow from high to low areas.
