Answer:
<em>70%</em>
<em></em>
Step-by-step explanation:
Given
Number of Siblings: || 0 || 1 || 2 || 3
Number of Students: || 4 || 18 || 10 || 8
Required
Determine the probability of a student having at least one but not more than 2 siblings
First, we have to determine the total number of 10th grade students
The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)
Solving for P(1)
P(1) = number of students with 1 sibling / total number of students
From the given parameters, we have that:
Number of students with 1 sibling = 18
So:
Solving for P(2)
P(2) = number of students with 2 siblings / total number of students
From the given parameters, we have that:
Number of students with 2 siblings = 10
So:
Take LCM
Divide numerator and denominator by 4
Convert to percentage
<em>Hence, the required probability is 70%</em>
<h3><u>S</u><u>olution</u></h3>
1). 1/3 + 1/5 = (5 + 3)/15
= 8/15. Ans.
2).
==> 3/5 - 1/6
= (3×5 - 5)/30
= (15 - 5)/30
= 10/30
= 1/3 Ans.
3).
==> 2/3 ÷ 3/4
= 2/3 × 4/3
= 8/9 Ans.
4).
==> 3/8 + 5/12
= (3×3 + 10)/24
= (9+10)/24
= 19/24 Ans.
5).
==> 5/16 - 3/32
= (5×2 - 3)/32
= (10-3)/32
= 7/32 Ans.
For #4, for any right triangle a^2 + b^2 should equal c^2. Square roots are just numbers to a power of 1/2. You can multiply the exponents together of #^(2 * 1/2) and simply get #. With that in mind, we can use sqrt2 as our a, sqrt3 as b, and sqrt5 as c, since c is always the largest number. For A, sqrt2 squared is 2, for B, sqrt3 squared is 3, and c is 5. Since 2+3 does indeed equal 5 you have a right triangle.
For #5, dilating by 3 means our length will be three times as long as whatever it is there. To find out how long the line is, we can make a right triangle. The differences between the x values are 6, and the differences between the y values are 12. A^2 + b^2 = c^2, 144 + 36 = 180, c= sqrt180, which is approx. 13.416. Multiply that by 3 and you get ≈40.25 as K’L’.
The commutative property of addition means we can add two integers in any order. So yes, It would still apply to two negative integers (for example, -2 + -3 and -3 + -2 both equal five)
