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Sav [38]
3 years ago
5

I don’t understand this please help

Mathematics
1 answer:
lesya [120]3 years ago
7 0
Answer for number 10

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The graph a linear function if passes through the point (3, -8) and has a slope of -2
Oksi-84 [34.3K]

Answer:

It's not 0 I got it wrong.

Step-by-step explanation:

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3 years ago
A deck is in the shape of a square. The area of the deck is 576 swuare feet. which is the length of each side of the deck
NNADVOKAT [17]
A) 24

All side lengths of a square are equal so you take the square root of 576 to get two 24. If you try it back: 24*24 (w*h) to get 576.
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A car travels 240 kilometers in 2 1/2 hours what is its speed
Oksanka [162]

Answer:

v = 96 km/h

Step-by-step explanation:

Data:

d = 240 km

t = 2.5 h

speed = d/t

speed = 240/2.5 = 96 km/h

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3 years ago
Can someone help me out with this problem
ohaa [14]

Answer:

\fbox {1) A}\\\fbox {2) A}

Step-by-step explanation:

<u>Q1</u>

⇒ Graph A is most accurate as the situation is linear and the dots indicate per cup as you can't have any rational part (such as 0.5 cups, etc.)

<u>Q2</u>

⇒ A

⇒ The graph is discrete because the sellers have limited the purchaser to buy a distinct whole number of cups

3 0
2 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
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