Answer:
There is an asymptote at x = 0
There is an asymptote at y = 23
Step-by-step explanation:
Given the function:
(23x+14)/x
Vertical asymptote is gotten by equating the denominator to zero
Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0
Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator
Coefficient of x at the numerator = 23
Coefficient of x at the denominator = 1
Ratio = 23/1 = 23
This means that there is an asymptote at y = 23
Answer:
h(t) = 16t changes 16 units every t. in the interval t=7 to t=2,
if its asking for:
then it's
16(2) - 16(7) = 32 - 112 = -80
Answer:
B and C
Step-by-step explanation:
2/3 = 6/9
and
1/2 = 4/8
