Answer:
No he can't
Step-by-step explanation:
8² = 64
10² = 100
8² + 10² = 164
18² = 324
For a right triangle A²+B²=C²
1. find our slope: y2 - y1/ x2- x 1
-9 + 4= -5
2 - 2 = 0
m = 0
2. now we need to use our point-slope form to find our y intercept
point-slope form: y - y1 = m(x - x1)
y + 4 = 0(x - 2)
distribute:
y + 4 = 0x
3. get y by itself
y + 4 - 4 = y
0x - 4 = 0x - 4
4. write in slope-intercept form:
y = 0x - 4
OR
y = -4
The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial
has solutions
, then you can factor it as

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

But this is a fourth-degree polynomial.
Answer:
x = 30
Step-by-step explanation:
Put in proportions
= 
Cross multiply and get 27x = 45 x 18
OR...
27x = 810.
THEN...
divide by 27 on both sides to get 30
x = 30
Answer:
C
Step-by-step explanation:
I explained in my last answer but someone deleted it