You would cross multiply the numbers to get 8x=15.
Then you would take away the 8 from both sides so you would divide it.
You are now left with x=1 7/8
Therefore that is your answer.
Hi okay i’m gonna write the explanation i hope you give me a brilliant if you think I’m deserving it thank you
(x-5)2=16
The first step you can take to solve this quadratic is to take the square root of both sides of the equation.
√[(x-5)2]=√(16)
When you take the square root of a term that is square it equals what is inside the parentheses.
So on the left side, you have x-5
On the right side, you are what we call "forcing" the square root. When this happens, you need to put ±. Why? Good question. When you square a negative number it positive; when you square a positive number it is also positive.
The √16 = ±4
So now we have;
x-5=±4
What do you do with that?
You make two separate equations.
x-5=4 and x-5=-4
x=9 x=1
Let's check our answers
x=9
(x-5)2=16
(9-5)2=16
42=16
16=16 it checks
x=1
(x-5)2=16
(1-5)2=16
(-4)2=16
16=16 it also checks
ANSWER: x=9 and x=1
Answer: is this an acute im confused
Step-by-step explanation:
Answer: 
Step-by-step explanation:


We need -9x on the left side, to move it, we must add 9x on both sides.

Done. We have Ax = 9x, By = 1y and C after the equal sign = -6
<span>(7y2 + 6xy) – (–2xy + 3)
7y^2 + 6xy +2xy +3
7y^2 +8xy +3
8xy + 7y^2 +3</span>