Question

Can I get some help on this problem please

Answer 1

We know that sum of angles of any quadrilateral is 360°.

The four angles are given as: x°, x°, 1/2 x° and 1/2 x°

$sum = 360 \\ \\ x + x + \frac{1}{2} x + \frac{1}{2} x = 360 \\ \\ \frac{2x + 2x + x + x}{2} = 360$

$\frac{6x}{2} = 360 \\ \\ 3x = 360 \\ \\ x = \frac{360}{3} = 120$

Thus, x = 120

The angles are:

$\frac{1}{2} x = \frac{1}{2} \times 120 = 60 \\ \\ \frac{1}{2} x = \frac{1}{2} \times 120 = 60$
$x = 120 \\ \\ x = 120 \\ \\ \boxed{all \: angles : {60}^{o}, \: {60}^{o} ,\: {120}^{o}, \: {120}^{o}}$