12 is the tital number of midfielders because since there are 3 people who make up 1/4 of the midfieldlers on the soccer team you need to miltiply 4 and 3 and 1/4 to count the total amount of midfeilders on the soccer team
(4)(3)=(1/4)(4)
Answer:
8x³ + 12x² - 16x - 16
General Formulas and Concepts:
- Order of Operations: BPEMDAS
- Distributive Property
Step-by-step explanation:
<u>Step 1: Define expression</u>
(4x² - 2x - 4)(2x + 4)
<u>Step 2: Simplify</u>
- Expand: 8x³ - 4x² - 8x + 16x² - 8x - 16
- Combine like terms (x²): 8x³ + 12x² - 8x - 8x - 16
- Combine like terms (x): 8x³ + 12x² - 16x - 16
Answer:
3a – 4b + 6c – 3d
when a = 5 b = 4 c = 3 d = 2
the value
= 3×5 - 4×4 + 6×3 - 3×2
=15-16+18-6
=11
Answer:
1/4 is the common ratio for the geometric sequence
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
