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Damm [24]
2 years ago
9

What is the transformation of A(6, 4) when dilated by a scale factor of 12,

Mathematics
1 answer:
kramer2 years ago
6 0
A(6,4) I know that OA and all that is something I do not know
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-4/2/5 = -3/1/5 + 7/10g
ludmilkaskok [199]

Answer:

g=12/7

Step-by-step explanation:

3 0
3 years ago
While creating your résumé, what should you do before making a final copy to fix any typos or errors?
Katyanochek1 [597]

Answer:

you could ask a friend or someone you are close to, to proof read it. You could also but it through Grammarly to find all errors that someone could just overlook.

5 0
3 years ago
Raoul bought 9 bags of granola mix. Each bag cost $5.59.<br><br> How much did Raoul spend?
IRINA_888 [86]

Answer:

$50.31

Step-by-step explanation:

9x5.59=50.31

An easy way to do it is take out the decimals and multiply. Then add the decimals by seeing how many places in 5.59 (2) and move the decimal 2 times on your answer.

7 0
3 years ago
Find an exact value.
Westkost [7]

Answer:

\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}.

Step-by-step explanation:

Convert the angle \displaystyle \left(-\frac{7\, \pi}{12}\right) to degrees:

\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ.

Note, that \left(-105^\circ\right) is the sum of two common angles: \left(-45^\circ\right) and \left(-60^\circ\right).

  • \displaystyle \cos\left(-45^\circ\right) = \cos\left(45^\circ\right) = \frac{\sqrt{2}}{2}.
  • \displaystyle \cos\left(-60^\circ\right) = \cos\left(60^\circ\right) = \frac{1}{2}.
  • \displaystyle \sin\left(-45^\circ\right) = -\sin\left(45^\circ\right) = -\frac{\sqrt{2}}{2}.
  • \displaystyle \sin\left(-60^\circ\right) = -\sin\left(60^\circ\right) = -\frac{\sqrt{3}}{2}.

By the sum-angle identity of cosine:

\cos(A + B) = \cos(A)\cdot \cos(B) - \sin(A) \cdot \sin(B).

Apply the sum formula for cosine to find the exact value of \cos\left(-105^\circ \right).

\begin{aligned}\cos\left(-105^\circ \right) &= \cos\left(\left(-45^\circ\right) + \left(-60^\circ\right)\right) \\ &= \cos\left(-45^\circ\right) \cdot \cos\left(-60^\circ\right)\right) - \sin\left(-45^\circ\right) \cdot \sin\left(-60^\circ\right)\right) \\ &= \frac{\sqrt{2}}{2} \times \frac{1}{2} - \left(-\frac{\sqrt{2}}{2}\right)\times \left(-\frac{\sqrt{3}}{2}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}\end{aligned}.

\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ. In other words, \displaystyle \left(-\frac{7\, \pi}{12}\right) and \left(-105^\circ\right) correspond to the same angle. Therefore, the cosine of \displaystyle \left(-\frac{7\, \pi}{12}\right)\! would be equal to the cosine of \left(-105^\circ\right)\!.

\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \cos\left(-105^\circ\right) = \frac{\sqrt{2} - \sqrt{6}}{4}.

3 0
3 years ago
1. Zaida opens her first social media account. Initially (Day 0), Zaida adds her 16 classmates in her math class as friends. Eac
Orlov [11]

The number of friends triples each day (16 x 3 = 48, 48 x 3 = 144, and so forth)

4 0
3 years ago
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