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2 years ago

What is the transformation of A(6, 4) when dilated by a scale factor of 12,

Mathematics

1 answer:

kramer2 years ago

6 0

A(6,4) I know that OA and all that is something I do not know

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-4/2/5 = -3/1/5 + 7/10g

ludmilkaskok [199]

Answer:

g=12/7

Step-by-step explanation:

3 0

3 years ago

While creating your résumé, what should you do before making a final copy to fix any typos or errors?

Katyanochek1 [597]

Answer:

you could ask a friend or someone you are close to, to proof read it. You could also but it through Grammarly to find all errors that someone could just overlook.

5 0

3 years ago

Raoul bought 9 bags of granola mix. Each bag cost $5.59.<br><br> How much did Raoul spend?

IRINA_888 [86]

Answer:

$50.31

Step-by-step explanation:

9x5.59=50.31

An easy way to do it is take out the decimals and multiply. Then add the decimals by seeing how many places in 5.59 (2) and move the decimal 2 times on your answer.

7 0

3 years ago

Find an exact value.

Westkost [7]

Answer:

$\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}$ .

Step-by-step explanation:

Convert the angle $\displaystyle \left(-\frac{7\, \pi}{12}\right)$ to degrees:

$\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ$ .

Note, that $\left(-105^\circ\right)$ is the sum of two common angles: $\left(-45^\circ\right)$ and $\left(-60^\circ\right)$ .

$\displaystyle \cos\left(-45^\circ\right) = \cos\left(45^\circ\right) = \frac{\sqrt{2}}{2}$ .
$\displaystyle \cos\left(-60^\circ\right) = \cos\left(60^\circ\right) = \frac{1}{2}$ .

$\displaystyle \sin\left(-45^\circ\right) = -\sin\left(45^\circ\right) = -\frac{\sqrt{2}}{2}$ .
$\displaystyle \sin\left(-60^\circ\right) = -\sin\left(60^\circ\right) = -\frac{\sqrt{3}}{2}$ .

By the sum-angle identity of cosine:

$\cos(A + B) = \cos(A)\cdot \cos(B) - \sin(A) \cdot \sin(B)$ .

Apply the sum formula for cosine to find the exact value of $\cos\left(-105^\circ \right)$ .

$\begin{aligned}\cos\left(-105^\circ \right) &= \cos\left(\left(-45^\circ\right) + \left(-60^\circ\right)\right) \\ &= \cos\left(-45^\circ\right) \cdot \cos\left(-60^\circ\right)\right) - \sin\left(-45^\circ\right) \cdot \sin\left(-60^\circ\right)\right) \\ &= \frac{\sqrt{2}}{2} \times \frac{1}{2} - \left(-\frac{\sqrt{2}}{2}\right)\times \left(-\frac{\sqrt{3}}{2}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}\end{aligned}$ .

$\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ$ . In other words, $\displaystyle \left(-\frac{7\, \pi}{12}\right)$ and $\left(-105^\circ\right)$ correspond to the same angle. Therefore, the cosine of $\displaystyle \left(-\frac{7\, \pi}{12}\right)\!$ would be equal to the cosine of $\left(-105^\circ\right)\!$ .

$\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \cos\left(-105^\circ\right) = \frac{\sqrt{2} - \sqrt{6}}{4}$ .

3 0

3 years ago

1. Zaida opens her first social media account. Initially (Day 0), Zaida adds her 16 classmates in her math class as friends. Eac

Orlov [11]

The number of friends triples each day (16 x 3 = 48, 48 x 3 = 144, and so forth)

4 0

3 years ago