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3 years ago

10

What is

5 \sqrt{9} \div 7 \sqrt{3} " alt="35 \sqrt{9} \div 7 \sqrt{3} " align="absmiddle" class="latex-formula">

1 answer:

mariarad [96]3 years ago

7 0

25.98076. So welcome my friend

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How do you solve 17 = 11y + 12x 12x + 11y = 14 in subsitution method?

Zolol [24]

You add 11y to 11y and 12x to 12x. then you have 17=22y+ 24x=14
-14 -14
14 cancels out. 3=22y+24x

8 0

4 years ago

Read 2 more answers

The Woodland Trail consists of four equal parts. If the entire trail is 1/2 of a mile long, how long is each part of the trail?

zhuklara [117]

Each part is 0.125 long

4 0

3 years ago

Sakura speaks 150150150 words per minute on average in Hungarian, and 190190190 words per minute on average in Polish. She once

d1i1m1o1n [39]

Answer:

300 words in Hungarian and 570 in Polish.

Step-by-step explanation:

I guess you need to know the number of words in Hungarian and in Polish.

Let H be the words he said in Hungarian, and P the words he said in Polish.

We are told that Sakura uttered a total of 270 more words in Polish than in Hungarian, therefore:

P = H + 270

And that I speak for 5 minutes, we know that the speed of words in Hungarian is 150 and in Polish it is 190, therefore:

5 = H / 150 + P / 190

Thus we have two equations and two unknowns, that is, it has a solution, replacing P:

5 = H / 150 + (H +270) / 190

5 = (190 * H + 150 * H + 270 * 150) / (150 * 190)

5 * 150 * 190 = 340 * H + 270 * 150

H = (5 * 150 * 190 - 270 * 150) / 340

H = 300

Therefore he said 300 words in Hungarian.

In Polish it would be:

P = 300 + 270 = 570

To check we have to:

300/150 + 570/190 = 5

Therefore, Sakura giving the instructions said 300 words in Hungarian and 570 in Polish.

8 0

3 years ago

Five boxes of candles contain a total of 60 candles. Each box holds the same number of candles. Complete the table and graph the

gizmo_the_mogwai [7]

Answer:

300

Step-by-step explanation:

you should muliple 60 and 5

4 0

3 years ago

7. Sky Castle Company is conducting research on 3 independent communities of 12 members each to see how they have been consuming

tresset_1 [31]

Answer:

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

Step-by-step explanation:

To solve this question, we need to use two separate binomial trials.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least 11 members being categorized as low risk participants.

12 members in the sample, so $n = 12$

30% chance to be categorized as high risk participants. So 100-30 = 70% probability of being categorized as low risk participants. So $p = 0.7$

This probability is

$P(X \leq 11) = P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{12,11}.(0.7)^{11}.(0.3)^{1} = 0.0712$

$P(X = 2) = C_{12,12}.(0.7)^{12}.(0.3)^{0} = 0.0138$

$P(X \leq 11) = P(X = 11) + P(X = 12) = 0.0712 + 0.0138 = 0.0850$

What is the probability that at least 11 members are categorized as low risk participants in two of three communities?

For each community, 8.50% probability of at least 11 members being categorized as low risk. So $p = 0.085$

Three comunities, so $n = 3$

This probability is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.085)^{2}.(0.915)^{1} = 0.0198$

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

6 0

3 years ago