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3 years ago

Pls tell me what is 152 + 466

Mathematics

2 answers:

iragen [17]3 years ago

8 0

Step-by-step explanation:

152 + 466=618 is your answer

kirza4 [7]3 years ago

3 0

The answer is 618

152

466

——-

618

Hope I helped you! :]

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Let x represent the measurment of an acute angle in degrees. the ratio of the complement of x to the supplement of x is 2: 5. gu

Nadusha1986 [10]

Ratio of complement of x : supplement of x
2 : 5
⇒ 2 times the supplement of x will be equal to 5 times the complement of x

5(90 - x) = 2 (180 - x)
450 - 5x = 360 - 2x
5x - 2x = 450 - 360
3x = 90
x = 30°

Complement of x = 90 - x = 90 - 30 = 60
Supplement of x = 180 - x = 180 - 30 = 150
Ratio:
60 : 150
60 ÷ 30 : 150 ÷ 30
2 : 5 (checked)

4 0

3 years ago

Please answer and fast

valentinak56 [21]

18- H
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Explanation:

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3 years ago

2/5 ÷ 22/35 <br>simplify

Sliva [168]

Answer:

7/11 (Simplified Already)

Step-by-step explanation: 25÷2235=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

25×3522=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

2×355×22=70110

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 70 and 110 using

GCF(70,110) = 10

70÷10110÷10=711

Therefore:

25÷2235=711

Solution by Formulas

Apply the fractions formula for division, to

25÷2235

and solve

2×355×22

=70110

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(70,110) = 10

70÷10110÷10=711

Therefore:

2/5÷22/35=7/11

6 0

4 years ago

Read 2 more answers

Which equation shows a line perpendicular to the line

LenaWriter [7]

Answer:

The second answer: y= 3/4x + 2

Step-by-step explanation:

Subtract 4x to the other side

Divide by 3 to get y by itself

Make the coefficient of the x term the negative reciprocal, for that is the perpendicular slope of the line

3 0

3 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

3 years ago