Find the length of side x in simplest radical form with a rational denominator.

What is the distance between begin ordered pair 8 comma negative 3 comma 4 end ordered pair and begin ordered pair 6 comma negat

katen-ka-za [31]

Answer:

$d = \sqrt{14} = 3.74...$

Step-by-step explanation:

To find the distance between (8, -3, 4) and (6, -4, 1), use the distance formula for (x,y,z) points. It is very similar to (x,y) points.

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2 - z_1)^2} \\d = \sqrt{(8 - 6)^2 + (-3--4)^2 + (4-1)^2} \\d = \sqrt{(2)^2 + (1)^2 + (3)^2} \\d = \sqrt{4 + 1 + 9}\\ d = \sqrt{14} = 3.74...$

5 0

3 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago

(7x - 1) + (-x - 2) in simplest terms

ch4aika [34]

Answer:

6x-3

Step-by-step explanation:

6 0

2 years ago

Two life insurance policies, each with a death benefit of 10,000 and a one-time premium of 500, are sold to a couple, one for ea

Kazeer [188]

Answer:896.9

Step-by-step explanation:

Let x denotes excess premium over claims

$E\left ( x|husband survives\right )$ , There are two possibilities

(i)Only husband survives

This can be possible with a possibility of 0.01

Claims=10,000

Premium collected $=2\times 500=1000$

Thus x=1000-10,000=-9000

(ii)Both husband and wife survives

This can occur with a probability of 0.96

Here claims will be 0 as both survives

Premium taken=1000

thus x=1000

The probability that the husband survives is the sum of above cases

=0.96+0.01=0.97

Hence the desired conditional Expectation $E\left ( x|Husband survives\right ) =0.01\times \left ( -9000\right )+0.96\times \left ( 1000\right )=896.9$

7 0

3 years ago

What is the experimental probability that Dan will roll a number 3 the next time he rolls the number cube?

Bad White [126]

The experimental probability changes every time he rolls the die but if its just the next roll he has a 1/6 chance of getting a 3

4 0

3 years ago