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2 years ago

Number 2: (look at pivture) 10 point

Mathematics

2 answers:

emmainna [20.7K]2 years ago

5 0

Answer:

I think it should be A.

Step-by-step explanation:

The first arrow represents 2, and the second arrow represents subtracting -3 from it, represented as -(-3). This means that the first part of the equation is 2 - (-3). Now you have to solve it. When subtraction is modeled like this with a negative number, it actually means addition. This means that the answer should be as simple as 2+3 because there were two negative signs. 2+3=5, so A should be the answer.

PolarNik [594]2 years ago

3 0

Answer:

Step-by-step explanation:

Because the arrow is going 2 in the right direction...so you have to have the 2 in the equation...

and the reason it equals 5 instead of a (-) number is because of the KCC rule

so basically the equation is 2+3

or if you don't want the long way just look at all of the equations...only one of the have a 2 in it so it is automatically the correct answer

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Use the commutative property to multiply 2.35 x 24

Alenkinab [10]

Answer:

2.35 x 24 = 56.4

Step-by-step explanation:

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2 years ago

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Do a proportion
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3 years ago

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timama [110]

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3 years ago

A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The

Oksanka [162]

Answer:

a) $[-0.134,0.034]$

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

$s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}$ ,

where $n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19$ .

The mean difference $\mu_1 - \mu_2 = 10.85 - 10.90 = -0.05$ .

The confidence interval is

$(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}$

$= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]$

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

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