Move decimal point to right side five times to get 5.7*10^-5. (5.7 multiply by 10 to the power of negative five) (This is the scientific notation)
Step-by-step explanation:
Given:

This field will have a scalar potential
if it satisfies the condition
. While the first x- and y- components of
are satisfied, the z-component doesn't.


Therefore the field is nonconservative so it has no scalar potential. We can still calculate the work done by defining the position vector
as

and its differential is

The work done then is given by



The probability of picking a ticket that is green or has a number greater than four is 3/5
<h3>How to determine the probability?</h3>
The given parameters are:
Yellow = 1 - 5
Green = 1 - 5
Total = 10
There are 2 cards whose numbers are greater than 4 i.e. Yellow 5 and Green 5
So, we have:
P(Number greater than 4) = 2/10
There are 5 green cards.
So, we have:
P(Green) = 5/10
Also, 1 green card is numbered greater than 4
So, we have:
P(Green greater than 4) = 1/10
The required probability is:
P = P(Green) + P(Number greater than 4) - P(Green greater than 4)
This gives
P = 5/10 + 2/10 - 1/10
Evaluate
P = 6/10
Simplify
P =3/5
Hence, the probability of picking a ticket that is green or has a number greater than four is 3/5
Read more about probability at:
brainly.com/question/11234923
#SPJ1
Answer:
It is $66.50 cheaper to purchase a return trip ticket than it is to purchase 2 one-way tickets.
Step-by-step explanation:
It is asking us how much does 2 one-way tickets costs as opposed to a return trip ticket. First, let's figure out how much does 2 one-way tickets cost.
Equation:
287.75 x 2 = 575.50
2 one-way tickets cost $575.50.
Then, to find the difference, subtract the return trip cost from the two one-way tickets.
Equation: 575.50 - 509.00 = 66.50
The difference between the two is $66.5
Conclusion: It is $66.50 cheaper to purchase a return trip ticket than it is to purchase 2 one-way tickets.
I hope this helps!