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3 years ago

10

Factorise the following :

2 answers:

timurjin [86]3 years ago

5 0

Answer:

2.

x³+2x²+5x+10

x²(x+2)+5(x+2)

taking common

(x+2)(x²+5) is your answer

a³-a²b²-ab+b³

taking common

a²(a-b²)-b(a-b²)

taking common

(a-b²)(a²-b)

Len [333]3 years ago

3 0

Answer:

See below

Step-by-step explanation:

$(ii) \\ \\ {x}^{3} + 2 {x}^{2} + 5x + 10 \\ \\ = {x}^{2} (x + 2) + 5(x + 2) \\ \\ = (x + 2)( {x}^{2} + 5) \\ \\ (iii) \\ {a}^{3} - {a}^{2} {b}^{2} - ab + {b}^{3} \\ \\ = {a}^{2} (a - {b}^{2} ) - b(a - {b}^{2} ) \\ \\ = (a - {b}^{2} )( {a}^{2} - b)$

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X + 1 / 2 - 1 = 1 / 4

Nimfa-mama [501]

First, make the mixed fraction into improper fraction,

x−12=54

Add 1/2 on both sides

x−12+12=54+12

Find LCM,

LCM is 4

x=54+1⋅22⋅2

x=54+24

Add

x=74

Or,

x=134

Or,

x=1.75

X=1.75 IS YOUR ANSWER!

Hope this helps!

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7 0

3 years ago

I WILL AKE YOU THE BRAINLIEST EASY QUESTION

avanturin [10]

Answer:

3rd choice

Step-by-step explanation:

9/5 = 18/10 = 1.8

All your numbers are between 1 and 2, and all have a fractional part that is a whole number of tenths. 1.3, 1.5, and 1.8 will be correctly shown by dots on the 3rd, 5th, and 8th marks.

6 0

4 years ago

Read 2 more answers

Determine the discriminant of x2 = 4. <br><br> A. 17 <br> B. 16 <br> C. -15 <br> D. -10

tino4ka555 [31]

The discriminant is b<span>²-4ac
We can rewrite x</span>² = 4 to x<span>² + 0x - 4 = 0
So a = 1, b = 0, c = -4
</span>Δ = 0 - 4 * 1 * -4
Δ = 16
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6 0

3 years ago

Read 2 more answers

Match each equation with a value of x that satisfies it

Alexus [3.1K]

Answer:

(x-2)^1/4=2 ---> 18

√x^2+7=4. ---> -3

^3√1-x=-1. ---> 2

Step-by-step explanation:

just did it on plato

5 0

3 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago