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2 years ago

Factorise the following :

Mathematics

2 answers:

timurjin [86]2 years ago

5 0

Answer:

x³+2x²+5x+10

x²(x+2)+5(x+2)

taking common

(x+2)(x²+5) is your answer

a³-a²b²-ab+b³

taking common

a²(a-b²)-b(a-b²)

taking common

(a-b²)(a²-b)

Len [333]2 years ago

3 0

Answer:

See below

Step-by-step explanation:

$(ii) \\ \\ {x}^{3} + 2 {x}^{2} + 5x + 10 \\ \\ = {x}^{2} (x + 2) + 5(x + 2) \\ \\ = (x + 2)( {x}^{2} + 5) \\ \\ (iii) \\ {a}^{3} - {a}^{2} {b}^{2} - ab + {b}^{3} \\ \\ = {a}^{2} (a - {b}^{2} ) - b(a - {b}^{2} ) \\ \\ = (a - {b}^{2} )( {a}^{2} - b)$

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Find f(-2) for the function f(x)=5x+14

Stels [109]

Answer:

f(-2)=(-11)

Step-by-step explanation:

f(-2)=5(-5)+14

=(-25)+14

=(-11)

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2 years ago

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Marizza181 [45]

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2 years ago

Which of the following statements are true of the discriminant? The discriminant is b2 – 4ac in the quadratic formula. The discr

steposvetlana [31]

A is true If im not mistaking

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2 years ago

Read 2 more answers

Lee spent $36 to purchase a combination of drinks, sandwiches, and chips for himself and his friends. A drink costs $2, a sandwi

valkas [14]

2x+4y+0.50z=36 represents the situation.

Step-by-step explanation:

Let,

Drinks = x

Sandwich = y

And,

Chips = z

Total amount on these items = $36

According to the statement;

$x(cost\ of\ one\ drink)+y(cost\ of\ one\ sandwich)+z(cost\ of\ one\ chips)=\ Total\ amount\ spent\\2x+4y+0.50z=36$

2x+4y+0.50z=36 represents the situation.

Keywords: Linear equations

Learn more about linear equations at:

#LearnwithBrainly

7 0

2 years ago

Please answer question three and four if you can :)<br> Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

3 years ago

Factorise the following :​

Factorise the following :