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3 years ago

Written as a simplified polynomial in standard form, what is the result when

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

Step-by-step explanation:

7x+10 - (x+2)^2

7x+10 - (x^2 + 2x + 4)

7x+ 10 - x^2 - 2x - 4

5x + 6 - x^2

then if u have to find the value of x then put the value of a = 1,b = 5,c = 6 in quadratic formula (-b + under root b^2 - 4ac / 2a) or (- b - under root b^2 - 4ac / 2a) it will gives the value of x...

HOPE it u..!!

edit - do let me knw that it's right or not..!!

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3 years ago

Read 2 more answers

Maria and farida has 250 beads altogether. After Maria used 18 beads to make a bracket and farida gave away 2/5 of her beads, th

Elenna [48]

Answer:

Maria had 105 beads at first.

Step-by-step explanation:

Let number of beads Maria have be x.

Let number of beads Farida have be y.

Given:

Maria and Farida has 250 beads altogether.

Hence equation is represented as;

$x+y =250 \ \ \ \ equation \ 1$

Also Given:

Maria used 18 beads to make a bracket.

hence bead left with maria = $x-18$

farida gave away 2/5 of her beads.

Hence beads left with Farida = $y - \frac{2}{5}y= \frac{5y}{5}-\frac{2y}{5}=\frac{5y-2y}{5}=\frac{3y}{5}$

Also they have the same number of beads left.

bead left with maria = beads left with Farida

$x-18= \frac{3y}{5}\\5(x-18)=3y\\5x-90=3y\\5x-3y =90 \ \ \ \ equation \ 2$

Now Multiplying equation 1 with 3 we get;

$3(x+y)=3\times250 = 3x+3y = 750 \ \ \ \ equation \ 3$

Now adding equation 2 by equation 3 we get;

$(5x-3y)+(3x+3y) = 750+90\\5x-3y+3x+3y = 840\\8x=840\\x=\frac{840}{8}=105$

we know the value of x = 105

hence substituting value of x in equation 1 we get;

$105+y=250\\y=250-105 =145$

Maria had 105 beads and Farida had 145 beads at first.

Final Answer: Maria had 105 beads at first.

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3 years ago

Solve for i in the following equation by means of linear interpolation (1 + i)^10 - 1/ i = 25

lesya692 [45]

Answer:

i = 0.5049202164

Step-by-step explanation:

the given equation is:

$\frac{(1+i)^{10-1}}{i} = 25 \\ \\ (1+i)^{10} = 25i + 1 \\ \\ (1+i)^{10}-25i = 1 \\ \\ Taking \ log \ of \ both \ sides ; we \ have: \\ \\ log(1+i)^{10} - log (25 \ i) = log (1) \\ \\ 10 \ log (1+i) - \ log \ (25 \ i) = 0 \ \ \ \ \ (since : log (1) = 0 )) \\ \\ \ log (1+i) = log \ (25 \ i) ^{1/10} \\ \\ log(1+i) = log (1.3627429+0.2158372i) \\ \\ 1+i = 1.3627429+0.2518372 \ i$

$[ 1 - 0.2518372]i = 1.3627429 -1 \\ \\ 0.784162729 = 0.3627429 \\ \\ i = \frac{0.3627429}{0.784162729} \\ \\ i = 0.5049202164$

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3 years ago