3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the graph is 0 because the line tangent to the point is horizontal. We can find the rate of change by taking the derivative of the function.
y' = 2ax + b
Now that we where the derivative, we can set it equal to 0.
2ax + b = 0
We also know that at the extreme value, x = -1/2. We can plug that in as well.

The 2 and one-half cancel each other out.


Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.
a(-0.5)^2 + a(-0.5) + 10 = 0
0.25a - 0.5a + 10 = 0
-0.25a = -10
a = 40
b = 40
To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.
80x + 40
Our critical number is x = -1/2. We need to plug a number that is less than -1/2 and a number that is greater than -1/2 into the derivative.
LESS THAN:
80(-1) + 40 = -40
GREATER THAN:
80(0) + 40 = 40
The rate of change of the graph changes from negative to positive at x = -1/2, therefore the extreme value is a minimum.
4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.
y' = 2ax + 1
2a(3) + 1 = 0
6a = -1
a = -1/6
So now plug the a value and x=3 into the original function to find the extreme value.
(-1/6)(3)^2 + 3 + 3 = 4.5
The extreme value is 4.5
-5/2 is the slope of thosr points
It would be c because this isn't transforming it
Answer:
45
Step-by-step explanation:
Answer:
we have to find the quotient and the remainder when (x³ + 5x + 3x² + 5x³ + 3) is divided by (x² + 4x + 2) ♥9 dividend = x² + 4x + 2 using Euclid division lemma, x² + 4x + 2) x² + 5x³ + 3x² + 5x + 3(x³ - 4x² + 19x - 65 x² + 4x² + 2x³ - 4x² + 3x² + 3x² - 4x*-16x³8x² 19x³ + 11x² + 5x 19x³ +76x² + 38x -65x²-33x + 3 -65x²-260x - 130 +227x + 133 Therefore the quotient is x² - 4x + 19x - 65 and remainder is 227x + 133