If she got a 100 on her last test the highest her average would be is an 87%
Answer:
B. s = 13753
Step-by-step explanation:
s - 10000 = 3753
To find value of s, add both sides by 10000
s - 10000 = 3753
+10000 +10000
-----------------------------------
s = 13753
Answer:
The flagpole's shadow is 16.875 feet longer than the man's shadow
Step-by-step explanation:
The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;
Height of the shadow=actual height of the flagpole×factor
where;
length of the flagpole's shadow=22.5 feet
actual height of the flagpole=32 feet
factor=f
replacing;
22.5=32×f
32 f=22.5
f=22.5/32
f=0.703125
Using this factor in the expression below;
Length of man's shadow=actual height of man×factor
where;
length of man's shadow=m
actual height of man=8 feet
factor=0.703125
replacing;
length of man's shadow=8×0.703125=5.625 feet
Determine how much longer the flagpole's shadow is as follows;
flagpoles shadow-man's shadow=22.5-5.625=16.875 feet
The flagpole's shadow is 16.875 feet longer than the man's shadow
Answer: 135 days
Step-by-step explanation:
Since the amount of time it takes her to arrive is normally distributed, then according to the central limit theorem,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
From the information given,
µ = 21 minutes
σ = 3.5 minutes
the probability that her commute would be between 19 and 26 minutes is expressed as
P(19 ≤ x ≤ 26)
For (19 ≤ x),
z = (19 - 21)/3.5 = - 0.57
Looking at the normal distribution table, the probability corresponding to the z score is 0.28
For (x ≤ 26),
z = (26 - 21)/3.5 = 1.43
Looking at the normal distribution table, the probability corresponding to the z score is 0.92
Therefore,
P(19 ≤ x ≤ 26) = 0.92 - 28 = 0.64
The number of times that her commute would be between 19 and 26 minutes is
0.64 × 211 = 135 days
Answer:
(1.5)x
Step-by-step explanation:
90 minutes = 1.5 hours therefore
if car travels x miles in 1 hour
then the care has to travel (1.5)x miles in 90 minutes
