What's the answer for this multiplication problem????
1 answer:
Answer:
see below
Step-by-step explanation:
You know the leading term will be the product of leading terms, so is ...
(x^2)(3x^2) = 3x^4 . . . . . matches choices A, B, C
The x^3 term of the product will be the sum of the products of x and x^2 terms, so is ...
(x^2)(2x) +(3x^2)(-5x) = 2x^3 -15x^3 = -13x^3 . . . . . matches choice A only
With very little work, we have identified the only viable answer choice:
3x^4 -13x^3 -x^2 -11x +6
_____
You can work out the product using the distributive property 4 times: multiply each term of one polynomial by all terms of the other. Then collect terms.
A reasonable alternative is to identify the partial products that will make up any given term of the answer. Above we have shown how to find the x^4 and x^3 terms. The x^2 term will be the sum of products (x^2)(constant) +(x)(x), for a total of 3 contributors to that. Similar to the x^3 term, the x term of the product will be the sum of products (x)(constant). Of course, the final constant term in the result is only the product of the constants in each factor.
If you go about this systematically, then errors will not creep in, regardless of which method you use.
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Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
36 - 28.27 = 7.73
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
36 - 28.27 = 7.73