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Luda [366]
3 years ago
7

What's the answer for this multiplication problem????

Mathematics
1 answer:
borishaifa [10]3 years ago
6 0

Answer:

  see below

Step-by-step explanation:

You know the leading term will be the product of leading terms, so is ...

  (x^2)(3x^2) = 3x^4 . . . . . matches choices A, B, C

The x^3 term of the product will be the sum of the products of x and x^2 terms, so is ...

  (x^2)(2x) +(3x^2)(-5x) = 2x^3 -15x^3 = -13x^3 . . . . . matches choice A only

With very little work, we have identified the only viable answer choice:

  3x^4 -13x^3 -x^2 -11x +6

_____

You can work out the product using the distributive property 4 times: multiply each term of one polynomial by all terms of the other. Then collect terms.

A reasonable alternative is to identify the partial products that will make up any given term of the answer. Above we have shown how to find the x^4 and x^3 terms. The x^2 term will be the sum of products (x^2)(constant) +(x)(x), for a total of 3 contributors to that. Similar to the x^3 term, the x term of the product will be the sum of products (x)(constant). Of course, the final constant term in the result is only the product of the constants in each factor.

If you go about this systematically, then errors will not creep in, regardless of which method you use.

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babunello [35]
Hi there
Let's order the transactions
on May 1. 150
less On May 20 100 books were sold

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Add on June 15 25 books arrived

Add On June 17, a shipment of 150 books arrived

So
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Hope it helps
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4 years ago
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Gre4nikov [31]

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3 years ago
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WARRIOR [948]
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3 years ago
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liraira [26]
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The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000
valina [46]

Answer: 61,750 miles

Step-by-step explanation:

Given : The p-value of the tires to outlast the warranty = 0.96

The probability that corresponds to 0.96 from a Normal distribution table is 1.75.

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Standard deviation : \sigma=1000\text{ miles}

The formula for z-score is given by  : -

z=\dfrac{x-\mu}{\sigma}\\\\\Rightarrow\ 1.75=\dfrac{x-60000}{1000}\\\\\Rightarrow\ x-60000=1750\\\\\Rightarrow\ x=61750

Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.

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