What's the answer for this multiplication problem????
1 answer:
Answer:
see below
Step-by-step explanation:
You know the leading term will be the product of leading terms, so is ...
(x^2)(3x^2) = 3x^4 . . . . . matches choices A, B, C
The x^3 term of the product will be the sum of the products of x and x^2 terms, so is ...
(x^2)(2x) +(3x^2)(-5x) = 2x^3 -15x^3 = -13x^3 . . . . . matches choice A only
With very little work, we have identified the only viable answer choice:
3x^4 -13x^3 -x^2 -11x +6
_____
You can work out the product using the distributive property 4 times: multiply each term of one polynomial by all terms of the other. Then collect terms.
A reasonable alternative is to identify the partial products that will make up any given term of the answer. Above we have shown how to find the x^4 and x^3 terms. The x^2 term will be the sum of products (x^2)(constant) +(x)(x), for a total of 3 contributors to that. Similar to the x^3 term, the x term of the product will be the sum of products (x)(constant). Of course, the final constant term in the result is only the product of the constants in each factor.
If you go about this systematically, then errors will not creep in, regardless of which method you use.
You might be interested in
Answer:
Explained below.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
(a)
The sample selected is of size <em>n</em> = 450 > 30.
Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.
The mean and standard deviation are:
So, the sampling distribution of sample proportion is .
(b)
Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:
Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.
(c)
The sample selected is of size <em>n</em> = 200 > 30.
Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.
The mean and standard deviation are:
So, the sampling distribution of sample proportion is .
(d)
Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:
Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.
(e)
The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.
And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.
So, there is a gain in precision on increasing the sample size.