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Dominik [7]
3 years ago
10

Math 3rd grade can anyone explain why is 48 ?? I thought that we need to plus 6 top 6 bottom and each side is 8 why 8 because 6+

2 is 8
So 6+6+8+8 = 24

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

It's 48

Step-by-step explanation:

The entire area of the rectangle would be length times width

The width is six, and the length is 8

6 times 8 is 48

btw, its asking for area

tiny-mole [99]3 years ago
7 0

Answer:

See, its divided into TWO squares/rectangles.

you have to solve with the numbers you have on each one.

so, for the covered in shade one, you do 6 times 2, which is 12.

for the "not covered" you need to find the second number for the square. Since it has equal sides, the other side will be 6.

for that one you do 6 times 6 which is 36.

now you add both of them.

36 + 12= 48.

You added them, you need to multiply them but do not mix both rectangles/ squares numbers  until the end

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Give an equation of a line that is parallel to −3x + 7y =4. Explain why your line is parallel to the given line and how you arri
koban [17]

Answer:

  3x -7y = 0

Step-by-step explanation:

Parallel lines have the same slope.

Changing the constant in a linear equation like this only changes the y-intercept. It has no effect on the slope of the line. So, we can change the constant from 4 to 0 and we will have a line with the same slope, parallel to the original, but with a different y-intercept.

The "standard form" of the equation of a line has the leading coefficient positive. We can make that be the case by using the multiplication property of equality, multiplying both sides of the equation by -1.

Parallel line:

  -3x +7y = 0

In standard form:

  3x -7y = 0

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3 years ago
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zloy xaker [14]

Answer:

What to prove, solve for?

6 0
3 years ago
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I can’t seem to find the value of n in this peoblem
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Answer:

9

Step-by-step explanation:

you can always use guess-and-check:

124 seems rather high

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(9)P(2) = 9!/7! = 9x8 = 72

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Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
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3 years ago
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