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Svetllana [295]
3 years ago
13

Find the value of unknown angle x,y,z,a,b,c with reasons and full process​

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

Step-by-step explanation:

x = 70 degree (being vertically opposite angles)

y + 70 degree =180 degree (being linear pair)

y = 180 - 70

y = 110 degree

In triangle,

x + 60 + misssing angle = 180 degree (sum of interior angles of a triangle)

70 + 60 + missing angle =180

130 + missing angle = 180

missing angle = 180 - 130

missing angle = 50 degree

c = missing angle (being vertically opposite angles )

c = 50 degree

x + missing angle = a (sum of two interior opposite angles is equal to the exterior angle formed)

70 + 50 = a

120 degree = a

a = b (being vertically opposite angle

120 =b

therefore b is 120 degree

Hence , a = 120 degree , b = 120 degree , c = 50 degree , x = 70 degree , y = 110 degree

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<h2>SEE BELOW</h2>

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<h3>to understand this</h3><h3>you need to know about:</h3>
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  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

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vertex:(-1,4)

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  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

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