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3 years ago

Please help :)))))))m)))e

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

6 0

Its 90 because its a L shaped will means its 90

wel3 years ago

4 0

Answer:

Step-by-step explanation:

The exterior angle theorem states that to find the exterior angle, you have to add the interior angles that you know. 60+30 = 90.

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D) Calculate the area of a circle with a circumference of 31.4 in.

dsp73

Answer:

A ≈ 78.54

Step-by-step explanation:

Area of a circle is A=πr^2

Since you do not know r (radius) you take the formula for the circumference of a circle (C=2πr), plug in 31.4 for C, and solve for r

Now that you have the radius of 4.99746521, you round it up to 5 and solve the area formula with 5 in as r.

4 0

2 years ago

Read 2 more answers

Find the slope of the line that passes through the points (-8, -3) and (2, 3)

Artyom0805 [142]

Answer:

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 8, - 3) and (x₂, y₂ ) = (2, 3)

m = $\frac{3+3}{2+8}$ = $\frac{6}{10}$ = $\frac{3}{5}$ → c

8 0

3 years ago

M is between N and O . MO = 15, and MN = 76. Find NO

I am Lyosha [343]

Answer:

Step-by-step explanation:

N___________________<u>M</u>_______O

76 15

NO = MN + MO = 76 + 15 = 91

8 0

3 years ago

Which equation describes the circle having center point (3,7) and the radius r=4 in Standard form

Annette [7]

The equation of circle in standard form is $(x - 3)^2 + (y - 7)^2 = 16$

<h3><u>Solution:</u></h3>

Given that circle having center point (3,7) and the radius r = 4

To find: equation of circle in standard form

<em><u>The equation of circle is given as:</u></em>

$(x - h)^2 + (y - k)^2 = r^2$

Where center (h,k) and radius r units

Given that center point (h , k) = (3, 7) and radius r = 4 units

Substituting the values in above equation of circle,

$(x - 3)^2 + (y - 7)^2 = 4^2\\\\(x - 3)^2 + (y - 7)^2 = 16$

Thus the equation of circle in standard form is $(x - 3)^2 + (y - 7)^2 = 16$

6 0

3 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago