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Marrrta [24]
3 years ago
8

7. Find the slope of the following equation. Simplify your answer.

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

d

Step-by-step explanation:

Rewrite in slope intercept form (move 5x to the right, divide both sides by 2, and reorder the terms)

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What is the slope intercept form of the linear equation that passes through the point (0, 9) and has a slope of -6?
STALIN [3.7K]

Answer:

y - 9 = -6( x - 0)

y - 9 = -6x + 0

y = -6x + 9

Step-by-step explanation:

7 0
3 years ago
A line passes through the point (-2, 4), and its y-intercept is (0,6). What is the equation of the line that is
MatroZZZ [7]

Answer:

y = -x + 9

Step-by-step explanation:

The line that passes through the points (-2,4) and (0,6) has a slope of 1, and a y intercept of 6. The equation to the first line is y = x + 6. and perpendicular lines always have the opposite, reciprocal slope of the other line. So the slope for the second line would be -1. A line with the slope of -1 and a point of (5,4) would contain the points (5,4) , (4,5) , (3,6) , (2,7) , (1,8) , and (0,9) , which is the y intercept for the second line. So the equation for the second line would be y = -x + 9

8 0
3 years ago
Prove that root 7 is irrational by the method of contradiction
Alchen [17]

Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

Therefore \sqrt7 is an irrational number.

8 0
3 years ago
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malfutka [58]
He should take breaks every 15 minutes and he should also eat a healthy snack and drink lots of water
4 0
3 years ago
Show all steps to find the product of -3x^3 + 2x - 4 and x^3 + x - 2.
Lana71 [14]

Answer:

  -3x^6 -x^4 +2x^3 -8x +8

Step-by-step explanation:

Use the distributive property 4 times.

  (-3x^3 + 2x - 4)×(x^3 + x - 2)

  = -3x^3(x^3 +x -2) +2x(x^3 +x -2) -4(x^3 +x -2) . . . . once

  = -3x^6 -3x^4 +6x^3 +2x^4 +2x^2 -4x -4x^3 -4x +8 . . . . 3 more times

  = -3x^6 +x^4(-3+2) +x^3(6 -4) +2x^2 +x(-4 -4) +8 . . . . group like terms

  = -3x^6 -x^4 +2x^3 -8x +8

7 0
2 years ago
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