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Flauer [41]
3 years ago
7

A mountain climber climbed a cliff 50 feet at a time. He did this 5 times in one day. What was the overall change in his elevati

on
Mathematics
1 answer:
Goshia [24]3 years ago
4 0

Answer:

Step-by-step explanation:

The overall change is -150 feet. 50 times 5 is 150 feet, and the mountain climber descended. Therefore, the change is -150 feet in elevation.

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Scorpion4ik [409]
Ok
distance formula

D=\sqrt{(x1-x2)^2+(y1-y2)^2}
given
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5=\sqrt{(-6+3)^2+(5-y)^2}
5=\sqrt{(-3)^2+(5-y)^2}
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factor
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set to zero
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3 years ago
What is less than 1/2 but greater than 2/8 what could I be
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Alex

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Step-by-step explanation:

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